e activation energy for the gas phase isomerization of cis-2-butene is 75.3 cis-CH3 CH=CHCH3 → trans-CH3 CH=CHCH3 e rate constant at 978 K is 1.92 × 10-4 s¯¹. The rate constant will be 0.0026 K. Submit Answer Retry Entire Group 9 more group attempts remaining
e activation energy for the gas phase isomerization of cis-2-butene is 75.3 cis-CH3 CH=CHCH3 → trans-CH3 CH=CHCH3 e rate constant at 978 K is 1.92 × 10-4 s¯¹. The rate constant will be 0.0026 K. Submit Answer Retry Entire Group 9 more group attempts remaining
Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Educational Text: Isomerization of cis-2-butene**
The activation energy for the gas phase isomerization of cis-2-butene is 75.3 kJ.
\[ \text{cis-} \text{CH}_3\text{CH}=\text{CHCH}_3 \rightarrow \text{trans-} \text{CH}_3\text{CH}=\text{CHCH}_3 \]
The rate constant at 978 K is \( 1.92 \times 10^{-4} \, \text{s}^{-1} \). The rate constant will be \( 0.00263 \, \text{s}^{-1} \) at ______ K.
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Transcribed Image Text:**Educational Text: Isomerization of cis-2-butene**
The activation energy for the gas phase isomerization of cis-2-butene is 75.3 kJ.
\[ \text{cis-} \text{CH}_3\text{CH}=\text{CHCH}_3 \rightarrow \text{trans-} \text{CH}_3\text{CH}=\text{CHCH}_3 \]
The rate constant at 978 K is \( 1.92 \times 10^{-4} \, \text{s}^{-1} \). The rate constant will be \( 0.00263 \, \text{s}^{-1} \) at ______ K.
**Interactive Elements:**
- **Submit Answer Button**: Validate your response by clicking this button.
- **Retry Entire Group Button**: Allows users to attempt the problem set again.
- **Attempts Indicator**: Users have 9 more group attempts remaining.
This section may involve calculating or providing a specific temperature value to complete the provided equation.
Expert Solution
Step 1: Given
Activation energy (Ea)= 75.3 KJ
Rate constant (K1)= 1.92×10-4 s-1
Temperature (T1)= 978K
Rate constant ()= 0.00263 s-1
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