e 5. for) = 23-v 23-0-0 ހ نات 23 Ⅱ. tú (0,1) |0|= 1 со folo z = 3√5 = 15 (cos (Etan) + ism (ET)) for 1:0, 1:2 -> Isolated Singularities 3 Another Z=0 in the numerator. 3

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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is there another isolated singularity z=0 on the numerator? surely there is no solution for e^1/z^2=0?

e
5. for) = 23-v
23-0-0
ހ
نات 23
Ⅱ.
tú (0,1)
|0|= 1
со
folo
z = 3√5 = 15 (cos (Etan) + ism (ET)) for 1:0, 1:2
-> Isolated Singularities
3
Another Z=0 in the numerator.
3
Transcribed Image Text:e 5. for) = 23-v 23-0-0 ހ نات 23 Ⅱ. tú (0,1) |0|= 1 со folo z = 3√5 = 15 (cos (Etan) + ism (ET)) for 1:0, 1:2 -> Isolated Singularities 3 Another Z=0 in the numerator. 3
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