e- 2 sin (otFigure 3 RL low-pass filterOc (calculated)fc (calculated)L=2.4 mHR=75 ohmsVout4. Write the transfer function (both magnitude and phase angle) of the RL low-pass filter of Figure 3above in terms of joo (or s)5. Determine and record below the cutoff frequencies of the circuit of Figure 3.radians / sechertz6. Sketch the straight-line approximations of the frequency responses for the RL low-pass filter onGraph 2 (see later). The cutoff frequencies for a RC low-pass filter are given as follows:1and fc2+RC00 =1T1RCTransfer function =Vout00₂2 πFor an RL low-pass filter, the cutoff frequencies are:Frequency response of a filter circuit is given by two graphs:● Voltage gain in dB versus frequencyPhase shift versus frequency.Voltage gain and phase shift for any frequency are determined by finding the transfer function of thecircuit. Transfer function is the ratio of output voltage phasor to the input voltage phasor.1111 RL=and feTRΣπ 2πLDetermine the magnitude and the phase angle of the Transfer function as functions of jo. Later youwill see that transfer function are written in terms of s. For the time being consider s= jo.

Answered: Image /qna-images/answer/09fa69bf-d874-4d2c-bb0e-df30d312ef73.jpg

Answered: e- 2 sin (ot Figure 3 RL low-pass…

e- 2 sin (ot Figure 3 RL low-pass filter L=2.4 mH R=75 ohms ||| Vout 4. Write the transfer function (both magnitude and phase angle) of the RL low-pass filter of Figure 3 above in terms of joo (or s)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Filter

A filter is a device or process which removes some of the unwanted features or components like frequencies from a signal in signal processing. The feature of filters is the complete or partial suppression of some part of the signal, and filtering is a class of signal processing. This most often means removing some frequency bands or some frequencies. In the frequency domain, the filters do not exclusively act, especially in the image processing field many other targets for filtering exist. Without having to act in the frequency domain, the correlations can be removed for certain frequency components and not for others. The filters are widely used in electronics and telecommunication, in television, radio, radar, audio recording, music synthesis, control systems, computer graphics, and image processing.

Question

e- 2 sin (ot
Figure 3 RL low-pass filter
Oc (calculated)
fc (calculated)
L=2.4 mH
R=75 ohms
Vout
4. Write the transfer function (both magnitude and phase angle) of the RL low-pass filter of Figure 3
above in terms of joo (or s)
5. Determine and record below the cutoff frequencies of the circuit of Figure 3.
radians / sec
hertz
6. Sketch the straight-line approximations of the frequency responses for the RL low-pass filter on
Graph 2 (see later).

The cutoff frequencies for a RC low-pass filter are given as follows:
1
and fc
2+RC
00 =
1
T
1
RC
Transfer function =
V
out
00₂
2 π
For an RL low-pass filter, the cutoff frequencies are:
Frequency response of a filter circuit is given by two graphs:
● Voltage gain in dB versus frequency
Phase shift versus frequency.
Voltage gain and phase shift for any frequency are determined by finding the transfer function of the
circuit. Transfer function is the ratio of output voltage phasor to the input voltage phasor.
111
1 R
L
=
and fe
T
R
Σπ 2πL
Determine the magnitude and the phase angle of the Transfer function as functions of jo. Later you
will see that transfer function are written in terms of s. For the time being consider s= jo.

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