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E (2) If 5 boys and 5 girls sit in a row randomly, what is the probability no two children of the same gender sit next to each other? ordwed arrangements 2.10 S: the total # 10!! 5!*5! + 5151 #S #E PLEI ๆ BE #(S 2.51.11 1 - 126

E (2) If 5 boys and 5 girls sit in a row randomly, what is the probability no two children of the same gender sit next to each other? ordwed arrangements 2.10 S: the total # 10!! 5!*5! + 5151 #S #E PLEI ๆ BE #(S 2.51.11 1 - 126

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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I don't understand how E = 5!*5!+5!*5!. I understand that E is equal to the number of ways 2 of the same genders can sit next to each other. Can you explain the logic and how my professor got E= 5!*5!+5!*5! ? 

E (2) If 5 boys and 5 girls sit in a row randomly, what is the probability no two children of the same gender sit next to each other? odwd arrangements что 5: the total Ħ #S #E 1 10! 5 !· 5! + 5 151 2.51 PLEI BE #S S 126
Transcribed Image Text:E (2) If 5 boys and 5 girls sit in a row randomly, what is the probability no two children of the same gender sit next to each other? odwd arrangements что 5: the total Ħ #S #E 1 10! 5 !· 5! + 5 151 2.51 PLEI BE #S S 126
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