-{ e-2, Cos x, x < 0 x>0

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
### Problem 5: Consider the Function

Given the function:
\[ 
f(x) = 
\begin{cases} 
e^{-x}, & \text{if } x < 0 \\
\cos x, & \text{if } x \geq 0 
\end{cases} 
\]

#### (a) Evaluate Limits and Continuity at \(x = 0\)
- Find the left-hand limit as \(x\) approaches 0: \(\lim_{x \to 0^-} f(x)\)
- Find the right-hand limit as \(x\) approaches 0: \(\lim_{x \to 0^+} f(x)\)
- Evaluate the function at \(x = 0\): \(f(0)\)
- Determine whether \(f\) is continuous at \(x = 0\), providing your reasoning.

#### (b) Sketch the Graph of the Function \(f(x)\)
- Visualize and draw the piecewise function based on the given conditions.

### Solution:

#### (a) Evaluating Limits and Continuity:

**Left-hand limit:**
\[
\lim_{x \to 0^-} f(x) = \lim_{x \to 0^-} e^{-x} = e^0 = 1
\]

**Right-hand limit:**
\[
\lim_{x \to 0^+} f(x) = \lim_{x \to 0^+} \cos x = \cos 0 = 1
\]

**Function value at \(x = 0\):**
\[
f(0) = \cos 0 = 1
\]

**Continuity at \(x = 0\):**
A function is continuous at \(x = 0\) if the following three conditions are met:
1. \(\lim_{x \to 0^-} f(x)\) exists.
2. \(\lim_{x \to 0^+} f(x)\) exists.
3. \(\lim_{x \to 0^-} f(x) = \lim_{x \to 0^+} f(x) = f(0)\).

Since \(\lim_{x \to 0^-} f(x) = \lim_{x \to 0^+} f(x) = f(0) = 1\), the
Transcribed Image Text:### Problem 5: Consider the Function Given the function: \[ f(x) = \begin{cases} e^{-x}, & \text{if } x < 0 \\ \cos x, & \text{if } x \geq 0 \end{cases} \] #### (a) Evaluate Limits and Continuity at \(x = 0\) - Find the left-hand limit as \(x\) approaches 0: \(\lim_{x \to 0^-} f(x)\) - Find the right-hand limit as \(x\) approaches 0: \(\lim_{x \to 0^+} f(x)\) - Evaluate the function at \(x = 0\): \(f(0)\) - Determine whether \(f\) is continuous at \(x = 0\), providing your reasoning. #### (b) Sketch the Graph of the Function \(f(x)\) - Visualize and draw the piecewise function based on the given conditions. ### Solution: #### (a) Evaluating Limits and Continuity: **Left-hand limit:** \[ \lim_{x \to 0^-} f(x) = \lim_{x \to 0^-} e^{-x} = e^0 = 1 \] **Right-hand limit:** \[ \lim_{x \to 0^+} f(x) = \lim_{x \to 0^+} \cos x = \cos 0 = 1 \] **Function value at \(x = 0\):** \[ f(0) = \cos 0 = 1 \] **Continuity at \(x = 0\):** A function is continuous at \(x = 0\) if the following three conditions are met: 1. \(\lim_{x \to 0^-} f(x)\) exists. 2. \(\lim_{x \to 0^+} f(x)\) exists. 3. \(\lim_{x \to 0^-} f(x) = \lim_{x \to 0^+} f(x) = f(0)\). Since \(\lim_{x \to 0^-} f(x) = \lim_{x \to 0^+} f(x) = f(0) = 1\), the
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