E 1.5 ft A 3 ft F D B 2 ft 1 ft 1 ft 20 kips From the frame above, determine the forces present. • Support reactions at A and B • Force at Bar EF Forces at Bar ACE (joints A, C, E)

Q: D В Bm 4m 3m A E G H 3m 3m 3m 3m 30KN 60KN 90KN

A:

Q: Three structural member(AB,BC, and CA) of equal lengths L, areas A, and elastic moduli E,…

A:

Q: F: ( Select) G: ( Select) 20 N 40 N 40 N 20 N F D 2 m H. E G 10 m KOOL Mo No- 4 m 4 m 4 m 2m 2m

A: To find the force in member DF , EF and EG

Q: force in BJ,AI,AB

A: As the truss is symmetrical :Ay=Hy=5F2=2.5800=2000kN

Q: 3 k/ft 6 t E 15k/ft 10 ft -18 ft- -18 ft-

A:

Q: H.W.: Draw the I. L. for the axial force in member BE for the truss shown below. E F H 3 m A 3 @4 m…

A: Considering the unit load at A: ∑Fy=0FBE=0

Q: F3-6 Determine the force in each member of the truss and state whether it is in tension or…

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Q: 1 50KN 2m A E B 30 4m с 3m R Reqdi All Thember forces

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Q: Solve for the internal reaction for each member of the truss using method of joints

A: Step 1: Step 2: Step 3: Step 4:

Q: Problem 2 The King-Post structure shown has a beam and three truss members. E = 29000 ksi, I = 400…

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Q: (d) 15 k 4 ft 10 k- 4 ft 7 k/ft 2 B -10 ft *Assume A to be pinned support, B to be roller, and C to…

A: To find out the support reaction of the structure.

Q: Determine force in member AB

A: Consider the figure, Here, T is the tension and C is the compression.

Q: Determine the reactions at the supports and the forces in the members of the truss shown with the…

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Q: - DETERMINE FORCES IN ALL MEMBERS IndiCATE WETHER FENSION I OR T COMPRESSION Гом A B 10m 30° гом So…

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Q: Find (a) the force in the bar BD,

A: Pin support is a type of support which can resist vertical and horizontal forces but do not…

Q: Prob. 6-61 6-62. In each case, determine the force P required to maintain equilibrium. The block…

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Q: 15k Q2: Assume the support at B is a roller. Determine the reactions at the supports. Take E=…

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Q: Determine the components of reactions of supports at A and B. REO IL

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Q: 1. Determine the support reactions of the frame shown: 15 KN 10 KN 4 m D. m- im- 3 m- -3 m-

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Q: *4-12 The truss is made of three A-36 steel members, each having a cross-sectional area of 400 mm².…

A: Sc= 0.0975 mmExplanation:

Q: The 3/5-in diameter pins at A and B that support the structure are in double shear. Neglecting the…

A:

Q: Determine the reactions on the frame at A and D.

A: Draw the reactions at A and D as shown below Consider Moment equilibrium at D, we get  Ax*0.5 =…

Q: (d) 15 k 10 k 4 ft 4 ft с 7 k/ft B -10 ft- *Assume A to be pinned support, B to be roller, and C to…

A:

Q: Question 4: The frame consists of right-angled triangles of base 2 m with angles as shown in Figure…

A: a) Support reaction:-                          ΣMD = 0-(20×6)-(30×4)-(40×2)+(RF×4) =0⇒            RF…

Q: did you find the axial reactions, how do you find that? at each supports (A and D)

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Q: 1600 lb B C D 4000 lb 2400 lb G 4 bays@12'-0"=48-0" 9-0"

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Q: 1. Compute the force in member FEF 2. Compute the force in member FED

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Q: Determine the force for member AB, GF, BC, CK, and BL.

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Q: L B Determine the reaction at the roller support and draw the bending moment diagram for the beam…

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Q: Solve for the internal reaction of member EF, BE, BC using method of sections

A: Step 1:  Step 2:

Q: 4 @ 4 m= 16 m A В C E G 60 kips H JK L 5 @ 3 m= 15 m-

A:

Q: AD using method of sections 24 KN 36 KN 4 m 4 m 4 m 4 m E 3 m 6 m

A: To find force in member BC, BD and AD

Q: w = 2P/L A B C 0.6L 0.2L 0.2L

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Q: 4. Select member FC and CB in the truss to carry the inclined force P. Set the allowable tensile…

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Q: 7. Calculate the force in the tie rod BC and the reaction at the pinned support at A for the rigid…

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Q: Determine the reaction at the support A of the frame. 5 kip 7 kip 10 kip 2 kip -6 ft- -8 ft -6 ft- 8…

A: Free Body Diagram of the given problem:

Q: 4 KN 3KN 5m č 5 m E Sm G 5m

A: given figure

Q: Determine the force in member EG and in member DF.

A:

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.