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dy vy(t) dt Submit awy²e-2at cos(wt) sin(wt) Part E w cos(wt) sin(wt) -yoe-at (a cos(wt) + w sin(wt)) Oyoe at (cos(wt) + aw cos(wt)) Ⓒ-ayo²e-2at Previous Answers ✓ Correct In this example we used both the chain and product rules of differentiation to obtain an expression for the (vertical) velocity-time relationship for the car from its position-time relationship. Evaluate the numerical value of the vertical velocity of the car at time t = 0.25 s using the expression from Part D, where yo = 0.75 m, a = 0.95 1/s, and w = 6.3 rad/s. ▾ View Available Hint(s)

dy vy(t) dt Submit awy²e-2at cos(wt) sin(wt) Part E w cos(wt) sin(wt) -yoe-at (a cos(wt) + w sin(wt)) Oyoe at (cos(wt) + aw cos(wt)) Ⓒ-ayo²e-2at Previous Answers ✓ Correct In this example we used both the chain and product rules of differentiation to obtain an expression for the (vertical) velocity-time relationship for the car from its position-time relationship. Evaluate the numerical value of the vertical velocity of the car at time t = 0.25 s using the expression from Part D, where yo = 0.75 m, a = 0.95 1/s, and w = 6.3 rad/s. ▾ View Available Hint(s)

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Evaluate the numerical value of the vertical velocity of the car at time t=0.25s using the expression from Part D, where y0=0.75m, α=0.951/s, and ω=6.3rad/s

 

vy(t) Submit Part E dy dt awyo²e-2at cos(wt) sin(wt) -ayo²e-2at w cos(wt) sin(wt) -yoe (a cos(wt) + w sin(wt)) yoe at (cos(wt) + aw cos(wt)) -at Previous Answers Correct In this example we used both the chain and product rules of differentiation to obtain an expression for the (vertical) velocity-time relationship for the car from its position-time relationship. Evaluate the numerical value of the vertical velocity of the car at time t = View Available Hint(s) 0.25 s using the expression from Part D, where yo = 0.75 m, a = 0.95 1/s, and w = 6.3 rad/s. Hint 1. Solving for the velocity The arguments of the trigonometric functions are in units of radians, so make sure your calculator is set for these units. Also, pay attention to precedence of operations when using a calculator to numerically evaluate the expression, including the algebraic sign of each value and term.
Transcribed Image Text:vy(t) Submit Part E dy dt awyo²e-2at cos(wt) sin(wt) -ayo²e-2at w cos(wt) sin(wt) -yoe (a cos(wt) + w sin(wt)) yoe at (cos(wt) + aw cos(wt)) -at Previous Answers Correct In this example we used both the chain and product rules of differentiation to obtain an expression for the (vertical) velocity-time relationship for the car from its position-time relationship. Evaluate the numerical value of the vertical velocity of the car at time t = View Available Hint(s) 0.25 s using the expression from Part D, where yo = 0.75 m, a = 0.95 1/s, and w = 6.3 rad/s. Hint 1. Solving for the velocity The arguments of the trigonometric functions are in units of radians, so make sure your calculator is set for these units. Also, pay attention to precedence of operations when using a calculator to numerically evaluate the expression, including the algebraic sign of each value and term.
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