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dy The standard form of the differential equation (1+t²) + 4ty = (1+t²)-2 is dt Select one: оа. dy 4t + 1 dt (1+ t?) = (1+t³ )² O b. dy dt (1+t)* 4t y = dt (1+ t²) = (1+ t² )-1 c. dy 4t + 1 dt (1+t)' (1+t²)³ O d. dy 4 1 + -y: dt (1+t) (1+t)

dy The standard form of the differential equation (1+t²) + 4ty = (1+t²)-2 is dt Select one: оа. dy 4t + 1 dt (1+ t?) = (1+t³ )² O b. dy dt (1+t)* 4t y = dt (1+ t²) = (1+ t² )-1 c. dy 4t + 1 dt (1+t)' (1+t²)³ O d. dy 4 1 + -y: dt (1+t) (1+t)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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dy The standard form of the differential equation (1+t²) + 4ty = (1+t²)-² is dt Select one: а. dy 4t 1 + dt (1+t)' (1+t²)² b. dy 4t y = (1+ t2 )-1 (1+t)* dt C. dy 4t 1 + y = dt (1+t) (1+t²)³ d. dy 4 y = (1+t) 1 + dt (1+t)
Transcribed Image Text:dy The standard form of the differential equation (1+t²) + 4ty = (1+t²)-² is dt Select one: а. dy 4t 1 + dt (1+t)' (1+t²)² b. dy 4t y = (1+ t2 )-1 (1+t)* dt C. dy 4t 1 + y = dt (1+t) (1+t²)³ d. dy 4 y = (1+t) 1 + dt (1+t)
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