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dy The solution of the differential equation dx 3x2 + 4x + 2 is 2(y – 1) (q) y = 1+ Vx3 + 2x2 + 2x + 4. If the initial condition is y(0) = 3, then the solution of the initial value problem is y = 6(x) = 1- Vr3 + 2x² + 2x + 4. %3D

dy The solution of the differential equation dx 3x2 + 4x + 2 is 2(y – 1) (q) y = 1+ Vx3 + 2x2 + 2x + 4. If the initial condition is y(0) = 3, then the solution of the initial value problem is y = 6(x) = 1- Vr3 + 2x² + 2x + 4. %3D

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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-2t -2t + czte (p) differential equation y" + 4y' + 4y = 4. Cje where C1 and C2 are arbitrary constants, is a solution of the dy The solution of the differential equation d.x 3x? + 4x + 2 is 2(y – 1) (q) y = 1+ Vx3 + 2x2 + 2x + 4. If the initial condition is y(0) = 3, then the solution of the initial value problem is y = $(x) = 1 – Væ³ + 2x² + 2x + 4.
Transcribed Image Text:-2t -2t + czte (p) differential equation y" + 4y' + 4y = 4. Cje where C1 and C2 are arbitrary constants, is a solution of the dy The solution of the differential equation d.x 3x? + 4x + 2 is 2(y – 1) (q) y = 1+ Vx3 + 2x2 + 2x + 4. If the initial condition is y(0) = 3, then the solution of the initial value problem is y = $(x) = 1 – Væ³ + 2x² + 2x + 4.
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