dy Solve (D +4D + 3)y= e' given y = 1, = 1 át t = 0! dt %3D %3D

Q: Solve for y at x=2: (4x^3 - 6yx^2 + 2xy^2)dx + (2yx^2 - 2x^3)dy = 0; y(1)=4

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Q: Calculate dy/dx. No need to expand answer. y=7x^2-9x+17/2x+4 dy/dx=

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Q: Identify the first order DE and show the solution for (x-x^3ye^-2y)dy-dx=0

A: Given the differential equation

Q: Find general solution of: 2x ( y - x^2) dx + dy = 0

A: Topic:- solution of differential equations

Q: Find the general solution of dy/dx=x-4/x^2-5x+6

A: Explanation of the answer is as follows

Q: 3. (y-x)dx = xy (x dx + y dy)

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Q: find dy/dx y = ecos(x+sqrt(x+lnx))^3

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Q: Would y = - (sqrt(16-x^2)) be a solution to dy/dx = -x/y with y(0) = -4?

A: The given differential equation  with

Q: Solve dy/dx =( y+x-2) /(y-x-4) Equation s reducible to homogenous form

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Q: dy/dx and d^2y/dx^2

A: Here; x=e-7t+2 .................. .......(1) y=6e2t+e-3t-4t   ......................(2)

Q: Sve SVé -3 dt u = Ve' – 3

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Q: Solve (1+x)dy-ydx=0

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Q: x(^2)+2xy+y(^3)=4 Find dy/dx

A: The given equation is

Q: Find dy/dx and d^2y/d^2x

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Q: Solve: x- dx dy - (x + 1)(1 + y*).

A: First separate the variables than integrate and solve the  differential equation .

Q: e^x + y)dx +(2 + X + ye^y)dy= 0 ,y(0)=1

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Q: dy/dt + 2y = e^(4t). Using the guessing method because 2 is constant. I need help solving this…

A: Solution of the first order differential equations

Q: Evaluate dy/dx @ the given point y^5-4=x^5-2y  @ (-1,1)

A: The given equation is  y5 - 4 = x5 - 2y We know that (d/dx) xn = nxn-1

Q: NON EXACT DE Solve: x(y^3 - x)dy-y(y^3 + x)dx=0

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Q: 2dy+ydx=y3(x-1)dx (Bernoulli)

A: We have to find the general solution of differential equations

Q: y"=? (d2y/dx2) y=2x2+1/x3+2x

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Q: Find the general solution to this exact equation: y + (2ty-e^(-2y) ) dy/dt = 0

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Q: solve for      xydy + 2(x^2 +2y^2)dy = 0 when x=0 and y=1

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Q: a) Let A and B be mutually exclusive events. Independent trials of the experiment are performed to…

A: There are two events A and B PA=paPB=pb a) Let A and B are mutually exclusive events. From the…