dy Given the equation x + xy + y =19. Find- dx %3D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Given the equation \(x^2 + xy + y^2 = 19\). 

Find \(\frac{dy}{dx}\).

**Solution Approach (Implicit Differentiation):**

To find \(\frac{dy}{dx}\) using implicit differentiation, follow these steps:

1. Differentiate both sides of the equation with respect to \(x\).
2. Apply the chain rule where necessary.
3. Solve for \(\frac{dy}{dx}\).

**Detailed Steps:**

- Differentiate \(x^2\) to get \(2x\).
- Differentiate \(xy\) using the product rule: the derivative is \(x \frac{dy}{dx} + y\).
- Differentiate \(y^2\) as \(2y \frac{dy}{dx}\).

Putting it all together:

\[
2x + (x \frac{dy}{dx} + y) + 2y \frac{dy}{dx} = 0
\]

- Rearrange to solve for \(\frac{dy}{dx}\).
Transcribed Image Text:**Problem Statement:** Given the equation \(x^2 + xy + y^2 = 19\). Find \(\frac{dy}{dx}\). **Solution Approach (Implicit Differentiation):** To find \(\frac{dy}{dx}\) using implicit differentiation, follow these steps: 1. Differentiate both sides of the equation with respect to \(x\). 2. Apply the chain rule where necessary. 3. Solve for \(\frac{dy}{dx}\). **Detailed Steps:** - Differentiate \(x^2\) to get \(2x\). - Differentiate \(xy\) using the product rule: the derivative is \(x \frac{dy}{dx} + y\). - Differentiate \(y^2\) as \(2y \frac{dy}{dx}\). Putting it all together: \[ 2x + (x \frac{dy}{dx} + y) + 2y \frac{dy}{dx} = 0 \] - Rearrange to solve for \(\frac{dy}{dx}\).
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