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dy Given a first order linear ODE in standard form dr -+p(1)y=g (1). To find the solution to this DE, an integrating factor (1)=P() is used to multiply both sides of the equation so that the left hand side of the equation is transformed into a derivative of a product (μµ(1)y (1)) Given y² + 2y = 2te-2¹,p(t) = 21 and hence the integrating factor is μ(1) =e£21² ore¹² O True O False

dy Given a first order linear ODE in standard form dr -+p(1)y=g (1). To find the solution to this DE, an integrating factor (1)=P() is used to multiply both sides of the equation so that the left hand side of the equation is transformed into a derivative of a product (μµ(1)y (1)) Given y² + 2y = 2te-2¹,p(t) = 21 and hence the integrating factor is μ(1) =e£21² ore¹² O True O False

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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dy dt - +p (1)y=g (1). To find the solution to this DE, an integrating factor µ(1) = e √p(1) d is used to multiply both sides of the equation so that the left hand side of the equation is transformed into a derivative of a product (µ (1)y (1))'. Given y' + 2ty = 2te d. p(t) = 21 and hence the integrating factor is µ(1) = √√2¹ ore ¹² -2 Given a first order linear ODE in standard form O True O False
Transcribed Image Text:dy dt - +p (1)y=g (1). To find the solution to this DE, an integrating factor µ(1) = e √p(1) d is used to multiply both sides of the equation so that the left hand side of the equation is transformed into a derivative of a product (µ (1)y (1))'. Given y' + 2ty = 2te d. p(t) = 21 and hence the integrating factor is µ(1) = √√2¹ ore ¹² -2 Given a first order linear ODE in standard form O True O False
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