dy Find dt y = (4+ csc 2t) dy %3D dt

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Find \(\frac{dy}{dt}\).

Given:
\[ y = (4 + \csc 2t)^{-6} \]

**Solution:**

To determine \(\frac{dy}{dt}\), apply the chain rule to differentiate the function \( y \) with respect to \( t \).

\[ \frac{dy}{dt} = \]

**Explanation of Concepts:**

- **Derivative**: The rate at which a function changes at any given point.
- **Chain Rule**: Used to differentiate composite functions. It states that \(\frac{d}{dt}[f(g(t))] = f'(g(t)) \times g'(t)\).
- **Cosecant Function (\(\csc\))**: Reciprocal of the sine function, given as \(\csc x = \frac{1}{\sin x}\).

Complete the solution using these principles.
Transcribed Image Text:**Problem Statement:** Find \(\frac{dy}{dt}\). Given: \[ y = (4 + \csc 2t)^{-6} \] **Solution:** To determine \(\frac{dy}{dt}\), apply the chain rule to differentiate the function \( y \) with respect to \( t \). \[ \frac{dy}{dt} = \] **Explanation of Concepts:** - **Derivative**: The rate at which a function changes at any given point. - **Chain Rule**: Used to differentiate composite functions. It states that \(\frac{d}{dt}[f(g(t))] = f'(g(t)) \times g'(t)\). - **Cosecant Function (\(\csc\))**: Reciprocal of the sine function, given as \(\csc x = \frac{1}{\sin x}\). Complete the solution using these principles.
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