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dy e-$x – 5ye¬Sx = 0e-5x Oe-Sx dx e-*y] = 0 dr

dy e-$x – 5ye¬Sx = 0e-5x Oe-Sx dx e-*y] = 0 dr

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I don't know how this actually works.

I dont know how we get (e^-5x)y.  

The image contains two mathematical expressions related to derivatives. 1. \(\frac{dy}{dx} e^{-5x} - 5y e^{-5x} = 0e^{-5x}\) This equation involves a derivative \(\frac{dy}{dx}\), an exponential \(e^{-5x}\), and a term including y. It is set equal to the expression \(0e^{-5x}\). 2. \(\frac{d}{dx} \left[ e^{-5x} y \right] = 0\) This is another equation involving a derivative \(\frac{d}{dx}\) of the product \(e^{-5x} y\), and it is set equal to zero. There are no graphs or diagrams included in the image.
Transcribed Image Text:The image contains two mathematical expressions related to derivatives. 1. \(\frac{dy}{dx} e^{-5x} - 5y e^{-5x} = 0e^{-5x}\) This equation involves a derivative \(\frac{dy}{dx}\), an exponential \(e^{-5x}\), and a term including y. It is set equal to the expression \(0e^{-5x}\). 2. \(\frac{d}{dx} \left[ e^{-5x} y \right] = 0\) This is another equation involving a derivative \(\frac{d}{dx}\) of the product \(e^{-5x} y\), and it is set equal to zero. There are no graphs or diagrams included in the image.
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