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d²y dy e* sin x . Using MỤC and substituting y, and its derivatives in the linear differential equation, Consider dx2 dx what is the simplified equation? -2 A cos x – 2 B e' sin x = e* sin x -2 A e* cos x – 2 B sin x = e* sin x -2 A cos x – 2 B sin x = sin x Ax e' cos x + B e* sin x = sin x

d²y dy e* sin x . Using MỤC and substituting y, and its derivatives in the linear differential equation, Consider dx2 dx what is the simplified equation? -2 A cos x – 2 B e' sin x = e* sin x -2 A e* cos x – 2 B sin x = e* sin x -2 A cos x – 2 B sin x = sin x Ax e' cos x + B e* sin x = sin x

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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d²y dy e* sin x . Using MỤC and substituting y, and its derivatives in the linear differential equation, Consider dx2 dx what is the simplified equation? -2 A cos x – 2 B e' sin x = e* sin x -2 A e* cos x – 2 B sin x = e* sin x -2 A cos x – 2 B sin x = sin x Ax e' cos x + B e* sin x = sin x
Transcribed Image Text:d²y dy e* sin x . Using MỤC and substituting y, and its derivatives in the linear differential equation, Consider dx2 dx what is the simplified equation? -2 A cos x – 2 B e' sin x = e* sin x -2 A e* cos x – 2 B sin x = e* sin x -2 A cos x – 2 B sin x = sin x Ax e' cos x + B e* sin x = sin x
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