d'y dx² ==y+sinx, y(0)=1.0, y(2) = 3.0. 0≤x≤2,

Q: 1. dy = e3x+2y dx

A: Given dydx = e3x+ 2y

Q: Solve for dy y = sec 2x² dx

A:

Q: Would y = - (sqrt(16-x^2)) be a solution to dy/dx = -x/y with y(0) = -4?

A: The given differential equation  with

Q: if x^2 + 3y^3 = 12, find dy/dx and evaluate (-2, -3)

A: To find the derivative

Q: If y=3(−7x^2+7x+1)^13, then      dy/dx=

A: Given:- y= 3(-7x2+7x+1)13 To find :- dy/dx

Q: 7+8i 4+5i 6–3i 8-4i

A:

Q: Find the partial derivative. xev10ry Əx

A:

Q: Differentiate the function. y = V7 + 4e3x y' = %3D

A: The function is  y=7+4e3x

Q: If f(x) = 5x2 – 6e* + sin4x, then f'(0) = O a. 6 O b. -6 О с. 2 O d. -2

A:

Q: y' = x2y2/x2+y2 ; is this function seperable or non-seperable

A:

Q: find (d^(2)y)/(dx^(2)). y=xcos(5x)-sin^(2)x

A: y=xcos5x-sin2x Differentiating with respect to x, we get…

Q: 8x V a8 + 5 dx =.

A:

Q: (x^2 -1) dy/dx +2xy =x

A:

Q: 2- Solution of the following function {(dy/dx)-(cotx) y=(csc x)y³ }

A: The differential equation is given as dydx-(cot x)y = (csc x)y31y3dydx-1y2cot x = csc x…

Q: 3x2 x³ +1 dx

A:

Q: y = 2" In (cot (Tx))

A:

Q: 8. (x² + 2xy − 4y²) dx — (x² − 8xy — 4y²) dy = 0. - -

A: #8

Q: d'y -+42=sin 2x 3 dx dx

A:

Q: dx² dx 543-5+ y = 0; y(0) = 4y'(0) = 0

A: To solv the following initial value problem.

Q: if S 3 then S f(x) dx = 43 and I f(x) f(x) dx = -2 -1 √ (3 Sin (x) - 4 fcx)) dx = ? -1

A:

Q: Solve for dx/y-xdy/y^2=0

A:

Q: y"+y=sec³x

A: The given equation is: y"+y=sec3x

Q: the

A:

Q: 2. Sx³(a² + x²)° dx ? + x?)% dx

A: Using property of integration,

Q: (3– 3cos5x)} (3x² +2x-7)² (e - sinx +3x) y= Find dy/dx if

A: That's computational, take a careful look.

Q: dy/dx = 6x^5sqrt(y-1) equals to y = [(1/2)(x^6+c)]^2 + 1? Diff eqn.

A: ∫tndt=tn+1n+1+cgiven  dydx=6x5y-1          dyy-1=6x5dxintegrate both sides