d²y dt² dy +5. dt + 6y = f (t).

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1. What is the Transfer Function of this Differential Equation?

2. Find the solution to the dierential equation in the time domain assuming y (t) = Aest (you are not allowed to use Laplace transforms). Use the initial conditions y (0) = 1/6 , y'(0) = 5, with f (t) = u(t). 

 

The equation shown is:

\[
\frac{d^2y}{dt^2} + 5 \frac{dy}{dt} + 6y = f(t).
\]

This is a second-order linear differential equation with constant coefficients. The equation involves the second derivative \(\frac{d^2y}{dt^2}\), the first derivative \(\frac{dy}{dt}\), and the function \(y(t)\) itself. The term \(f(t)\) represents a forcing function, which can be any function of \(t\), such as a constant, polynomial, exponential, or sinusoidal function, depending on the context of the problem. The coefficients 5 and 6 are constants determining the behavior and characteristics of the solution. This type of equation commonly appears in modeling physical systems, such as mechanical vibrations, electrical circuits, or control systems.
Transcribed Image Text:The equation shown is: \[ \frac{d^2y}{dt^2} + 5 \frac{dy}{dt} + 6y = f(t). \] This is a second-order linear differential equation with constant coefficients. The equation involves the second derivative \(\frac{d^2y}{dt^2}\), the first derivative \(\frac{dy}{dt}\), and the function \(y(t)\) itself. The term \(f(t)\) represents a forcing function, which can be any function of \(t\), such as a constant, polynomial, exponential, or sinusoidal function, depending on the context of the problem. The coefficients 5 and 6 are constants determining the behavior and characteristics of the solution. This type of equation commonly appears in modeling physical systems, such as mechanical vibrations, electrical circuits, or control systems.
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