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dy _ y x dx y use y=ux substitution which ode do we obtain? O A) x(du/dx)¬u^2 O B) (x+u)(du/dx)=l/u OC) x(du/dx)=1/u O D) x+(du/dx)=l/u O E) x(du/dx)-u

dy _ y x dx y use y=ux substitution which ode do we obtain? O A) x(du/dx)¬u^2 O B) (x+u)(du/dx)=l/u OC) x(du/dx)=1/u O D) x+(du/dx)=l/u O E) x(du/dx)-u

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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dy y x y - dx y 35 - use y=ux substitution which ode do we obtain? O A) x(du/dx)-u^2 O B) (x+u)(du/dx)=1/u C) x(du/dx)=1/u O D) x+(du/dx)=1/u E) x(du/dx)=u
Transcribed Image Text:dy y x y - dx y 35 - use y=ux substitution which ode do we obtain? O A) x(du/dx)-u^2 O B) (x+u)(du/dx)=1/u C) x(du/dx)=1/u O D) x+(du/dx)=1/u E) x(du/dx)=u
Expert Solution
Step 1

Using the product rule of derivative, it can be written that ddx(pq)=pdqdx+qdpdx .

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