dy - (2xy + y ²) 2+ dx B) Write the equation for the tangent line where x = 2 and y = 1. (2,1) 16 FL dy dx (2,1) H -(2(2)(1) + 1² 22 +2.2.1 Mach THCK y = - =//(x-2) + 1 (4+1) 4+4 11 C) Find the coordinates of the point (x, y) where the curve has a horizontal tangent line. slope 0 = (аху ту + y²) x² + 2xy 2x C 0 = - 2xy - Y 0=Y (-2x-y) 2

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