dy 16x The direction field for = dx 25y is shown to the right 4 (a) Verify that the straight lines y = x are solution curves, provided x * 0. (b) Sketch the solution curve with initial condition y(0) = -3. (c) Sketch the solution curve with initial condition y(2) = 1. (d) What can be said about the behavior of the above solutions as x→ + ∞o? How about x→→ ∞o? O D. The solution does not exist for positive x. What can be said about the behavior of the solution in part (b) as x→→∞o? Select the correct choice below and necessary, fill in the answer box to complete your choice. O A. As x→→∞o, the solution approaches 4 and has the line y = 5x as an asymptote. 4 and has the line y = -x as an asymptote. O B. As x→→∞o, the solution approaches OC. The solution does not approach a single value or +∞ as x→→ 00.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
dy 16x
The direction field for =
25y
dx
is shown to the right.
4
(a) Verify that the straight lines y = 5x are solution curves, provided x* 0.
(b) Sketch the solution curve with initial condition y(0) = -3.
(c) Sketch the solution curve with initial condition y(2) = 1.
(d) What can be said about the behavior of the above solutions as x→ + ∞o?
How about x→-00?
D. The solution does not exist for positive x.
What can be said about the behavior of the solution in part (b) as x→ ∞o? Select the correct choice below and, if
necessary, fill in the answer box to complete your choice.
O A. As x→→∞o, the solution approaches
4
and has the line y = x as an asymptote.
4
and has the line y = -x as an asymptote.
Q
O B. As x→→∞o, the solution approaches
OC. The solution does not approach a single value or too as x→→∞0.
O D. The solution does not exist for negative x.
Transcribed Image Text:dy 16x The direction field for = 25y dx is shown to the right. 4 (a) Verify that the straight lines y = 5x are solution curves, provided x* 0. (b) Sketch the solution curve with initial condition y(0) = -3. (c) Sketch the solution curve with initial condition y(2) = 1. (d) What can be said about the behavior of the above solutions as x→ + ∞o? How about x→-00? D. The solution does not exist for positive x. What can be said about the behavior of the solution in part (b) as x→ ∞o? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. As x→→∞o, the solution approaches 4 and has the line y = x as an asymptote. 4 and has the line y = -x as an asymptote. Q O B. As x→→∞o, the solution approaches OC. The solution does not approach a single value or too as x→→∞0. O D. The solution does not exist for negative x.
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