dy 1. FIND BY IMPLICIT DIFFERENTIATION: 9x = secy dx dy 2 a) FIND BY IMPLICIT DIFFERENTIATION: x4y³ = -8 dx b) EVALUATE THE DERIVATIVE FROM PART a AT THE POINT (1, -2). 3. FIND THE SLOPE OF THE TANGENT LINE TO THE GRAPH OF 5x + 2xy + 4y² = 25 AT THE POINT (1,2). 4. FIND BY IMPLICIT DIFFERENTIATION: x² + y² = 81 13
dy 1. FIND BY IMPLICIT DIFFERENTIATION: 9x = secy dx dy 2 a) FIND BY IMPLICIT DIFFERENTIATION: x4y³ = -8 dx b) EVALUATE THE DERIVATIVE FROM PART a AT THE POINT (1, -2). 3. FIND THE SLOPE OF THE TANGENT LINE TO THE GRAPH OF 5x + 2xy + 4y² = 25 AT THE POINT (1,2). 4. FIND BY IMPLICIT DIFFERENTIATION: x² + y² = 81 13
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![E:
1. FIND
dy
BY IMPLICIT DIFFERENTIATION: 9x =
dx
secy
2 a) FIND
dy
BY IMPLICIT DIFFERENTIATION: x*y3 = -8
dx
b) EVALUATE THE DERIVATIVE FROM PART a AT THE POINT (1, -2).
3. FIND THE SLOPE OF THE TANGENT LINE TO THE GRAPH OF 5x + 2xy + 4y² = 25 AT THE POINT (1,2).
d²y
4. FIND
dx?
BY IMPLICIT DIFFERENTIATION: x2 + y² = 81](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fec2b8ded-7417-4214-b76c-ce26c6ed6817%2F569fc56d-6627-4575-b31e-555526c3eff3%2Fqlaknu_processed.png&w=3840&q=75)
Transcribed Image Text:E:
1. FIND
dy
BY IMPLICIT DIFFERENTIATION: 9x =
dx
secy
2 a) FIND
dy
BY IMPLICIT DIFFERENTIATION: x*y3 = -8
dx
b) EVALUATE THE DERIVATIVE FROM PART a AT THE POINT (1, -2).
3. FIND THE SLOPE OF THE TANGENT LINE TO THE GRAPH OF 5x + 2xy + 4y² = 25 AT THE POINT (1,2).
d²y
4. FIND
dx?
BY IMPLICIT DIFFERENTIATION: x2 + y² = 81
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