-dx. V1–16z² Consider For the u-substitution u = 1 – 16x², which is the new integrand in terms of u?

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.4: Fractional Expressions
Problem 57E
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dx.
/1–16z²
Consider
For the u-substitution u = 1 – 16x², which is the new integrand in terms of u?
32
12
Transcribed Image Text:dx. /1–16z² Consider For the u-substitution u = 1 – 16x², which is the new integrand in terms of u? 32 12
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