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dx x2 – 64 First, rewrite this with partial fractions: S, da = f 1/(x+8) dx + [ 1/(x-8) dr = log(x+8) log(x-8) +C. 12-64 (Note that you should not include the +C in your entered answer, as it has been provided at the end of the expression.) Next, use the substitution w = r? 64 to find the integral: S da = S x^2-64 dw = +C = In(x^(2)-64) +C. 1 (For the second answer blank, give your antiderivative in terms of the variable w. Again, note that you should not include the +C in your answer.)

dx x2 – 64 First, rewrite this with partial fractions: S, da = f 1/(x+8) dx + [ 1/(x-8) dr = log(x+8) log(x-8) +C. 12-64 (Note that you should not include the +C in your entered answer, as it has been provided at the end of the expression.) Next, use the substitution w = r? 64 to find the integral: S da = S x^2-64 dw = +C = In(x^(2)-64) +C. 1 (For the second answer blank, give your antiderivative in terms of the variable w. Again, note that you should not include the +C in your answer.)

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 21T
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dx x2 – 64 First, rewrite this with partial fractions: S, da = f 1/(x+8) dx + [ 1/(x-8) dr = log(x+8) log(x-8) +C. 12-64 (Note that you should not include the +C in your entered answer, as it has been provided at the end of the expression.) Next, use the substitution w = r? 64 to find the integral: S da = S x^2-64 dw = +C = In(x^(2)-64) +C. 1 (For the second answer blank, give your antiderivative in terms of the variable w. Again, note that you should not include the +C in your answer.)
Transcribed Image Text:dx x2 – 64 First, rewrite this with partial fractions: S, da = f 1/(x+8) dx + [ 1/(x-8) dr = log(x+8) log(x-8) +C. 12-64 (Note that you should not include the +C in your entered answer, as it has been provided at the end of the expression.) Next, use the substitution w = r? 64 to find the integral: S da = S x^2-64 dw = +C = In(x^(2)-64) +C. 1 (For the second answer blank, give your antiderivative in terms of the variable w. Again, note that you should not include the +C in your answer.)
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