dx dx +8. + 16x = (for t> 0). di dt 1+2

Q: Differentiate d dx y = 11x4 + 3 - (1₁x² + 3) =

A: As we know that

Q: 65. + 1 dr RVT -x dx 66.

A: We’ll answer the 65th question since we answer only one question at a time. Please submit a new…

Q: 2 1-6 (5x-ex) dx =

A:

Q: 04 * O O Evaluate -1+2x-2x^2 -1+2x+2x^2 -1-2x-2x^2 -1-2x+2x^2 d dx 1-x fe 1² dt).

A:

Q: Differentiate dx y=3x²+2 (3x² + 2) = 3+.

A:

Q: sec® x dx cot x SE V

A: We can evaluate the given integral by using the substitution u= tan x and the following formulas.…

Q: 2x+x-21x+24 dx x² +2x-8

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Q: 3 So 20 x² +9 dx

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Q: (4cscxcotx + 2 sec² x)dx

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Q: d Differentiate (-16x-1 +4x + 2) when x dx

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Q: (4 dx 2 2X Sxー X-I

A:

Q: (ど4ー) 2dx 4 X(3(Inx)*+121nx-15)2 2)

A:

Q: -| Vx³ + 16x² dx

A: Let I=∫x3+16x2 dx I=∫xx+16 dx Let assume x+16=t2⇒dx=2t dt I=∫(t2-16)t(2t) dt =2∫(t4-16t2)dt

Q: dx V4 - x - dx 2 8)

A:

Q: d.x 2x2 +3x + 1 0. 2.

A:

Q: Explain why

A: Given: I=∫−111x3dx≠0

Q: Зх +6 dx 2x2 + 8х + 3 (Inx)? dx 5. 6.

A:

Q: бх + 20 4. 522 — dx 186х — 8

A: This can be solved easily by integrating properly and expanding the terms.

Q: 3 Evaluate: ((5x* – 2x' + 3x – 4)dx 3 S(-x'- + 4х -1)dx Evaluate: 1

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Q: dx XV. xVx2-4

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Q: da d²y +6- dx dx² + 11 dx+6y = ex + cosx бу

A:

Q: Differentiate y = 11x4 +3

A: given to find

Q: Evaluate dx

A: To find- Evaluate ∫01x2 ln1x3dx      Formula Used-  ∫ u v dx = u ∫v dx - ∫ddxu ∫v dxdx

Q: Evaluate 1 xVx5 +3 dx 0.

A:

Q: tan³/3x secº/3x

A: Given that, ∫tan33xsec63xxdx

Q: 3-6xе* dx= X

A: NOTE: Refresh your page if you can't see any equations. .

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.