dx -4ху) 2x²–y² dy dx ||

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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How does this happen?

How does one goes from eq 1 to eq 2?

Thus, the acceleration of the particle at point (1 m, 1 m) is 17 m/s².
Write the expression for the slope of flow in a streamline flow (dyldx).
dy
dx
dy
(-4xy)
dx
2x?-y?
(I)
(2x² – y² ) dy = –4xydx
2x? dy — y? dy + 4хydx %3D 0
Obtain the differentiation of (2x²y).
d (2x²y)
= 2 (2xydx + x²dy)
= 4xydx + 2x?dy
Rewrite Equation (I) using the above differentiation.
d (2r²y) – y°dy = 0
(II)
2r²y – = c
(1 m)
= C
2(1 m)² (1 m)
C = {
Rewrite Equation (II).
y -
6x²y – y° = 5
5+y
x² =
Transcribed Image Text:Thus, the acceleration of the particle at point (1 m, 1 m) is 17 m/s². Write the expression for the slope of flow in a streamline flow (dyldx). dy dx dy (-4xy) dx 2x?-y? (I) (2x² – y² ) dy = –4xydx 2x? dy — y? dy + 4хydx %3D 0 Obtain the differentiation of (2x²y). d (2x²y) = 2 (2xydx + x²dy) = 4xydx + 2x?dy Rewrite Equation (I) using the above differentiation. d (2r²y) – y°dy = 0 (II) 2r²y – = c (1 m) = C 2(1 m)² (1 m) C = { Rewrite Equation (II). y - 6x²y – y° = 5 5+y x² =
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