dx = 3 cos° x/2sinx

Q: Sinx=1/2 Cos2x=

A:

Q: dx2 16y = 10 cos 4x

A:

Q: 2. ( sin32x dx cos 2x

A: We have to integrate.

Q: S sin 2x sin 4x dx 7.

A:

Q: sin(2w)dw =

A:

Q: Sec (Cosx) dydx 1- Sin

A:

Q: -3RT/2 b. Smt cos³x sinx dx

A:

Q: Classify and Solve dy cos x +y sinx = cosx dx

A:

Q: COs 2x cotx x – tanx %3D sinx · cOsx

A:

Q: 3x dx 1. S 2x 4-1

A:

Q: cos 3x = √3/2 x =

A: Given that cos3x=32. Find the value of x.                     The formula used are the following.…

Q: Solve (cosx)dy = (sinx)dx

A: The objective is to solve the expression cosxdy=sinxdx

Q: y = sin 2rx

A:

Q: 2a xsin " dx 1.

A:

Q: sin6x 5. S 4sin?3xcos3x

A:

Q: y = cos(-4x)

A:

Q: Solve (sin?3x)dy = dx

A: We have to solve the given expression    The given expression is   (sin2 3x) dy =dx

Q: L{2tcos2t + sin2t}=

A: The Laplace transform of a function f(t) is given by;

Q: 7/2 d sin dx dx COS

A:

Q: y = Secx ( sinx+ Cosx)

A: Given, y=secxsinx+cosx And we have to find the dydx.

Q: Find Se2" sin(2x)dæ

A:

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.