dwu527.jpg ñ A Q Search 3904444433359GCO Collab.com/collab/ui/session/playback Good Morning Def f(x,T) (Y,V) is cont. if SEX Fly (f(s)) ex X= {xER: 1x12 1}¸ T= Subspace top- from R, usual) Y = {0, 1], V = discrete top f:X + Y has f(x) = { ₁ bo4EE if x²-1 if X 21 claim f is Cont. Case S has a a pt. We show f(cs) Ecl(f(s)) n 4-1 and a pt. ²1 S Q Search 316 X > 5 case Let S S [1,00). Notice f(s)={1}. Then clxs=₁ X = [1,00) X = [1,00). So cl(S) ≤ [1] ? ▷ Case Let 64 Then f (c1(s)) = {1}. So f (cl s ) ² = {¹} = C]y ([¹]) = cly (f(s) ) ↑ [17 is closed in (Y, V) SG (-00,-1]. (HW) FS

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Hello, can you please look this example and follow similar format and please solve sufficiently on paper

dwu527.jpg
^
Q Search
3.1
344444443SCOGCO 66
collab.com/collab/ui/session/playback
Good Morning
ETS
Def f: (x,T) → (Y, V) is cont. if
* SEX, f(cs) ≤cl( f(s))
ex X= {x€R: 1×1² 1}¸ T= subspace top-
from (iR, usual)
-I
claim f is Cont.
Y = {0, 1} V = discrete top
f: X→Y has f(x) = { 0₁ if x 4-1
if X 21
pt.
bo4EEEESEEEEEO3
Case S has a
We show f(clŚ) Ecl(f(s)) -
4-1 and a pt. ²1
D
Q Search
Δ
313 Bb
X
Case Let
ETS
MEC
case Let S ≤ [1,00). Notice
f(s) = {1}. Then
IR
clxs = c/₁RSX = [1,00)^X = [1,00),
So cl(s) ≤ [1,~]
3
Then f (c1(s)) = {1}.
So f (cl S) == {¹} = cly ([¹]) = cly (f(s) )
↑
{1} is closed in (Y, V)
SC (-00,-1].
(HW)
SSO
Transcribed Image Text:dwu527.jpg ^ Q Search 3.1 344444443SCOGCO 66 collab.com/collab/ui/session/playback Good Morning ETS Def f: (x,T) → (Y, V) is cont. if * SEX, f(cs) ≤cl( f(s)) ex X= {x€R: 1×1² 1}¸ T= subspace top- from (iR, usual) -I claim f is Cont. Y = {0, 1} V = discrete top f: X→Y has f(x) = { 0₁ if x 4-1 if X 21 pt. bo4EEEESEEEEEO3 Case S has a We show f(clŚ) Ecl(f(s)) - 4-1 and a pt. ²1 D Q Search Δ 313 Bb X Case Let ETS MEC case Let S ≤ [1,00). Notice f(s) = {1}. Then IR clxs = c/₁RSX = [1,00)^X = [1,00), So cl(s) ≤ [1,~] 3 Then f (c1(s)) = {1}. So f (cl S) == {¹} = cly ([¹]) = cly (f(s) ) ↑ {1} is closed in (Y, V) SC (-00,-1]. (HW) SSO
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