Answered: dw de - 3 cms dt Fird t when w-4cm and…

Name: I pretty much understand what's going on in this problem except for th
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Description: I pretty much understand what's going on in this problem except for the part circled in green. My question is, why do we multiply the rate of change for length by width, and the rate of change for width by length. I thought length needed to be multip

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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I pretty much understand what's going on in this problem except for the part circled in green. My question is, why do we multiply the rate of change for length by width, and the rate of change for width by length. I thought length needed to be multiplied by rate of change for length. Thanks.

dw.
20m/s.
de = 3cms
Find
t when w-4cm and R=5cm
A-l.w
dA
4-prodrule
al
dA
dt
4(3)+562)
12+103D220m/s

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