dv mg – kv, m- dt
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
Transcribed Image Text:An object of mass m
falling near the
surface of the earth is
retarded by air
resistance proportional
to its velocity so
that, according to
Newton's Second Law of
Motion,
dv
m-
= mg – kv,
dt

Transcribed Image Text:dv
m
= mg – kv,
dt
where v=v (t) is the
velocity of the object
at time t, and g is the
acceleration of gravity
near the surface of the
earth. Assume that the
object falls from rest
at time t=0, that is
v ( 0 ) = 0 .
The velocity of the
object at time t=m/k is
v (m/k) =
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