dv ja-jo dt = = а = пр dt = 9.81 [1-v² (10-)] m/s² пр 1 [1 − (0.01 v)²] 9.81 [1 ['dt = ["+ S = 9/2 Put the value of a 7-311-12 (10-1)] dv = dt = 9.81 9.8150 In пр 2 (1+0.01v) 1+0.01 1-0.01, dv 2 (1-0.01v) 9.81t 50 In 1+0.01 (2). 1-0.01 Assume, I toolv = P => dv= 100p ? -1718-6 dv 9.31 [1-(16)7] ар = 9.31 [1-(0.011)] 9-81 лр (1+0.01) (1-0.010) + 9.81 2(1+0.01V) ༢〔Lv. av dv
dv ja-jo dt = = а = пр dt = 9.81 [1-v² (10-)] m/s² пр 1 [1 − (0.01 v)²] 9.81 [1 ['dt = ["+ S = 9/2 Put the value of a 7-311-12 (10-1)] dv = dt = 9.81 9.8150 In пр 2 (1+0.01v) 1+0.01 1-0.01, dv 2 (1-0.01v) 9.81t 50 In 1+0.01 (2). 1-0.01 Assume, I toolv = P => dv= 100p ? -1718-6 dv 9.31 [1-(16)7] ар = 9.31 [1-(0.011)] 9-81 лр (1+0.01) (1-0.010) + 9.81 2(1+0.01V) ༢〔Lv. av dv
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
I just had a question on the step that I marked blue, how did they get the number (2) please explain in details - please do not overcomplicate
![ja-jo
dt =
=
dt =
dt =
ข
dv
9.81 [1-v² (10-)] m/s²
dv
9.81 [1-(0.01)³]
dv
dv
['dt = ["d
dv
=
a
Put the value of a
9-311-121011]
dv
9.811
dv
dt
9.81
2 (1+0.01v)
2 (1-0.01v)
9.31 [1-(16)7]
1+0.01
t=
50 In
9.81
1-0.01
9.81t 50 In
1+0.01
(2).
1-0.01
?
9.81
dv
9.31 [1-(0.011)]
9-81
dv
(1+0.01) (1-0.010)
Assume, Ito.olv = p
=> dv= 100p
dv
2 (1+0.01)
100 dp
2 P
= 504yp
= (506 (1+0.01)
Similarly
dv
=
== Soby (1-0.01v))
9.81
_
dv
2(1+0.01)
+
dv
2(L-ཋ.»ry〕
+༢(ད- ༠-༠)
11/17 (50l02 (1+0.011) - Soly (1-0.01)
9.81
1(H.
-
-0.01V
t = 11311 [50 42
9.81
9.81+=
1-0.01v
1+0.01v](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe933bc49-41c0-49a8-92f9-d1ccbbfebc81%2Fa549e517-fe7b-4fd6-b73d-e93257fdb53f%2Fbvil1na_processed.png&w=3840&q=75)
Transcribed Image Text:ja-jo
dt =
=
dt =
dt =
ข
dv
9.81 [1-v² (10-)] m/s²
dv
9.81 [1-(0.01)³]
dv
dv
['dt = ["d
dv
=
a
Put the value of a
9-311-121011]
dv
9.811
dv
dt
9.81
2 (1+0.01v)
2 (1-0.01v)
9.31 [1-(16)7]
1+0.01
t=
50 In
9.81
1-0.01
9.81t 50 In
1+0.01
(2).
1-0.01
?
9.81
dv
9.31 [1-(0.011)]
9-81
dv
(1+0.01) (1-0.010)
Assume, Ito.olv = p
=> dv= 100p
dv
2 (1+0.01)
100 dp
2 P
= 504yp
= (506 (1+0.01)
Similarly
dv
=
== Soby (1-0.01v))
9.81
_
dv
2(1+0.01)
+
dv
2(L-ཋ.»ry〕
+༢(ད- ༠-༠)
11/17 (50l02 (1+0.011) - Soly (1-0.01)
9.81
1(H.
-
-0.01V
t = 11311 [50 42
9.81
9.81+=
1-0.01v
1+0.01v
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