dv g) tan(x- y) = y 1+x² d 1/₂ (tan ex-x) = $x (1+x) dx dx Sec² (x-y). (1-dy) = dx Sec ³ (x-y) - dy + d sec² (x-y) · —— (x²-y) = (1 + x) · ** - Y- £x (1-x) dy dx (1+x²) Sec²³(x-1). dx = dy dx (1+x²³² = (1+x). Jy - y. (0 +ax) (1+x). (1+x) (1+x² + sec ³ (x-1)). 2 sec³(x-4) + 2xy sec ³ (x-Y). dy Jx = dr 1 Final Answe Seca Ix-X + Se. dy (1 + x²³) Jx = seca (x-y)+ axy Cit dy = sel³ (x-1) + axy. Se (1+x) - CI
dv g) tan(x- y) = y 1+x² d 1/₂ (tan ex-x) = $x (1+x) dx dx Sec² (x-y). (1-dy) = dx Sec ³ (x-y) - dy + d sec² (x-y) · —— (x²-y) = (1 + x) · ** - Y- £x (1-x) dy dx (1+x²) Sec²³(x-1). dx = dy dx (1+x²³² = (1+x). Jy - y. (0 +ax) (1+x). (1+x) (1+x² + sec ³ (x-1)). 2 sec³(x-4) + 2xy sec ³ (x-Y). dy Jx = dr 1 Final Answe Seca Ix-X + Se. dy (1 + x²³) Jx = seca (x-y)+ axy Cit dy = sel³ (x-1) + axy. Se (1+x) - CI
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Related questions
Question
Please find the derivative dy/dx of the following function.
Is this right?
![g) tan(x - y) =
1+x²
d
1/² (tan ex-x) = // (1+x)
dx
dx
Címo
Sec² (x-y)- $ x (x²-y) = (1 + x) · X · Y. √x (1+x)
dx
Sec² (x-y). (1-dy) =
(1+x).
(1+x²2
/x-y. (0+2x)
dy
Sera (x-y)- Seca (x-y).
(1+x² + sec ³ (x-1))
seco(x-1)+ axy
(1+x)
(1+x)2
• d = 1 1
dx
T
h) Secx=xtany
+ sec (X-Y)
Final Answer
Secalx-x + xy
(1+x²)
+ Sei CX-Y)
+ x³
· dy + sec³(x-1). dx = sec ² (x-x)+ axy
Cittaja
1+x²
H
dy.
XY
Jx (1 + x)²
sec (x-1) + 2xy
(1+x)
Final Answer](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbed15dc4-f7d5-4c59-88ec-c5b05b5850af%2F52e62052-eb50-4065-847a-3e943703d28e%2Fvk84pnp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:g) tan(x - y) =
1+x²
d
1/² (tan ex-x) = // (1+x)
dx
dx
Címo
Sec² (x-y)- $ x (x²-y) = (1 + x) · X · Y. √x (1+x)
dx
Sec² (x-y). (1-dy) =
(1+x).
(1+x²2
/x-y. (0+2x)
dy
Sera (x-y)- Seca (x-y).
(1+x² + sec ³ (x-1))
seco(x-1)+ axy
(1+x)
(1+x)2
• d = 1 1
dx
T
h) Secx=xtany
+ sec (X-Y)
Final Answer
Secalx-x + xy
(1+x²)
+ Sei CX-Y)
+ x³
· dy + sec³(x-1). dx = sec ² (x-x)+ axy
Cittaja
1+x²
H
dy.
XY
Jx (1 + x)²
sec (x-1) + 2xy
(1+x)
Final Answer
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