Duse cholesky method to solve the followi ng linearsystem of equationss 4x,+X2+ s x3=5 X」+ YXL +子メ3- 2 5X+7X +16X3=6 %3D %3D

Q: General solution of 2xydx+y^2dy=0

A:

Q: у" +10y' + 25у %30

A: Given the differential equation is y" + 10y' + 25y = 0. Here the auxiliary equation is m2 + 10m + 25…

Q: Find a real general solution 5x^2 y"+23xy′+16.2y=0

A: Consider y=xm and solve using this substitution to obtain the required general solution.

Q: Obtain the general solution. 1. (D^4 - 5D^2 - 6D - 2)y = 0 2. (D^2 - 2D + 2)y = 0

A:

Q: Solve using method of undetermined coefficients (D2 + 4D + 5) = 13e3x + 50x When x=0, y=0, y'=0

A: Solution is given below:

Q: Match the items in colu A wh the equations of the quadratie fnctions in oolum Column A Colume A…

A:

Q: 1/5x+1/7y=12/5 1/10x+1/3y=5/6 use elimination method or has dependent equation

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Q: Q1\calculate x1, x2, xn from the following equations: -3x1 + 9x2 + Xn = 2 5x1 - 2x2 + 3x,n = -1 2x1…

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Q: 1. 5х2у" + 23ху' + 16.2у —D 0 2. х?у" + 0.7ху' — 0.1у %3D 0 3. х2у" — 0.7ху — 0.1у %3D0 |

A: Given

Q: 2x^3y"-x(2-5x)y'+y=0 Find the general solution using a point at infinity

A: Given- 2x3y''-x2-5xy'+y=0 To find- The general solution.

Q: use the two phase method to solve the lp MAX -  4x1  +  x2 - 2x3 st --    2x1 + 2x2 + x3 = 4 x 1+…

A: We can solve this using two phase method

Q: Solve 3x^2=6x-3 by graphing. Select the solutions given in the photo. (Show work)

A: Equation of vertex form is y=ax-h2+k; where (h,k) is the vertex.

Q: 1. 5у" + y' 3 -6х, у (0) %3D 0, у'(0) — —10 ||

A:

Q: Find a particular solution to the given​ higher-order equation.   y′′′−4y′′+y′+6y=-30t^2+8t+37

A: We have to find a particular solution to the given​ higher-order equation. y′′′ − 4y′′ + y′ + 6y =…

Q: Solve (D2+20D+200)y = 10 O y = e-10x (c₁sin10x + c₂cos10x) + 20 Oy=e-10x (c1sin10x + c₂cos10x) +…

A: Given

Q: Solve for x: 3x -y = 2 - 3y 2-4y ox = V +2 %3D 2-2y %D 3 - %3D 3. O x = 2 - 2y - 3 3.

A: Let us consider an equation ax+by=c  Then solution for x is given as, x= (c-by)/a

Q: 5. Solve IVP у" - 4y" + 7y - бу %3D 0, у(0) %3D 1, у'(0) — 0, у" (0) — 0

A: See the attachment

Q: Q2: Solve 1- y// + y = secx

A: As per the company's guidelines, we are supposed to answer the first question for you, Kindly repost…

Q: How do I find the general solution to this separable equation?

A: Topic - differential Equation We will solve this equation by variable separation method

Q: Solve of the following system: — 3^1 + 22 — 2"з — —7 5x1 + 3x2 – 4.3 = 2 - X1 + 2x2 – 3x3 = -1

A:

Q: 12 z² + \82c - 3

A: given function is solved with the help of differentiation rule i.e. Quotient rule (fg) = gf'-fg'g2…

Q: 2 Solve: 2(3)"-3 + 6 = 20 0/1 GIVE EXACT solution Show Your Work

A: Given equation 2(3) x-3+6=20

Q: 2r2-12r+18=o 2x+12x+21=O 2. yL+2x-Y=D

A:

Q: Solve by Simplex Method Subject to Max Z = 2x₁ + x₂ 3x₁ + x₂ ≤ 3 x₁ + 3x₂ ≤ 3 X1, X₂ 20

A: Given  Max Z=2x1+x2Subject to 3x1+x2≤3x1+3x2≤3x1,x2≥0

Q: 3 3 ( xy² + y ² ) dy = ( x ²³ y ²³ + x ³ - y ³ - 1 ) dx

A:

Q: А сurve bas equation y%3 (x+3}x* -3х+6). Explain wһу у%3(х+3Xx*-3х+6) is always positive for x>-3.

A: The solution is :

Q: -[3x+(8x+1)]=6-(2x+4) Linear equation with on variable

A: Given,

Q: S 10x+11 dx 4x²-4x+5

A: We will evaluate the given integral in the following steps.

Q: Solve using chain rule 1. y=(2x+1)(4x-3)^3 2. y=x √ 9-x^2

A:

Q: elimination of first degree variable: 2x/3 - y/2 = 1

A: The given equation is: 2x3-y2=1

Q: у" +4y' + 4y %3D0

A: Given the differential equation y" + 4y' + 4y = 0. Here the auxiliary equation m2 + 4m + 4 = 0