During this lab time, you are asked to building a 5-way tree of integers (but not a B-tree). So you don't need to consider the balance of the tree and there is no minimum requirement of entries in a node. You may use the following structures.
During this lab time, you are asked to building a 5-way tree of integers (but not a B-tree). So you don't need to consider the balance of the tree and there is no minimum requirement of entries in a node. You may use the following structures.
Computer Networking: A Top-Down Approach (7th Edition)
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![During this lab time, you are asked to building a 5-way tree of integers (but
not a B-tree). So you don't need to consider the balance of the tree and there
is no minimum requirement of entries in a node. You may use the following
structures.
#define Mul 5
typedef struct
int
data;
struct node* rightPtr;
} ENTRY;
typedef struct node
struct node* firstPtr;
int
numEntries;
entries [Mul - 1];
ENTRY
} NODE;
typedef struct
int
count;
NODE* root;
} MTREE;
The basic idea of above algorithm is as follows. Since we released the balance
requirement, the tree now is building from top to bottom.
if (root is nul1)
create a root and insert integer, return
else set root as node
loop
If (node is null)
create a node and insert integer, return
else if (the node is not full)
insert the integer into the node at a correct position, return
else //the node is full
find out the correct subtree to go and set node as that subtree
end loop](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F11f8c08f-6e04-4922-9703-5b86a73d91e8%2Fc16c7344-782b-4673-a0a9-b6beca7b8f24%2Fvp3tzqq_processed.png&w=3840&q=75)
Transcribed Image Text:During this lab time, you are asked to building a 5-way tree of integers (but
not a B-tree). So you don't need to consider the balance of the tree and there
is no minimum requirement of entries in a node. You may use the following
structures.
#define Mul 5
typedef struct
int
data;
struct node* rightPtr;
} ENTRY;
typedef struct node
struct node* firstPtr;
int
numEntries;
entries [Mul - 1];
ENTRY
} NODE;
typedef struct
int
count;
NODE* root;
} MTREE;
The basic idea of above algorithm is as follows. Since we released the balance
requirement, the tree now is building from top to bottom.
if (root is nul1)
create a root and insert integer, return
else set root as node
loop
If (node is null)
create a node and insert integer, return
else if (the node is not full)
insert the integer into the node at a correct position, return
else //the node is full
find out the correct subtree to go and set node as that subtree
end loop
Transcribed Image Text:Create 200 random numbers and use your program to build the 5-tree.
Then write a traverse function to print out these numbers in order.
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