During the first 13 weeks of the television season, the Saturday evening 8:00 p.m. to 9:00 p.m. audience proportions were recorded as ABC 31%, CBS 26%, NBC 27%, and independents 16%. A sample of 300 homes two weeks after a Saturday night schedule revision yielded the following viewing audience data: ABC 93 homes, CBS 72 homes, NBC 87 homes, and independents 48 homes. Test with a = 0.05 to determine whether the viewing audience proportions changed. State the null and alternative hypotheses. O Ho: PABC = 0.31, P CBS = 0.26, PNBC = 0.27, PIND = 0.16 H: The proportions are not PABC = 0.31, PCBS = 0.26, PNBC - 0.27, PIND = 0.16. Ho: PABC = 0.31, P CBS - 0.26, PNBC = 0.27, PIND = 0.16 H: PABC * 0.31, PCBS * 0.26, PNBC * 0.27, PIND * 0.16 Ho: The proportions are not PABC = 0.31, PCBS = 0.26, PNBC = 0.27, PIND = 0.16. H: PABC = 0.31, P CBS = 0.26, PNBC = 0.27, PIND - 0.16 %3D %3D %3D = 0.31, PCBS * 0.26, PNBC * 0.27, PIND 0.16 Hoi PABC H: PABC - 0.31, PCBS = 0.26, PNBC = 0.27, PIND = 0.16 Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. Reject H. There has been a significant change in the viewing audience proportions. Reject Ho. There has not been a significant change in the viewing audience proportions. Do not reject Ho. There has been a significant change in the viewing audience proportions. Do not reject H,e: There has not been a significant change in the viewing audience proportions.
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.
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During the first 13 weeks of the television season, the Saturday evening 8:00 p.m. to 9:00 p.m. audience proportions were
recorded as ABC 31%, CBS 26%, NBC 27%, and independents 16%. A sample of 300 homes two weeks after a Saturday night
schedule revision yielded the following viewing audience data: ABC 93 homes, CBS 72 homes, NBC 87 homes, and
independents 48 homes.
Test with a = 0.05 to determine whether the viewing audience proportions changed.
State the null and alternative hypotheses.
Ho: PABC = 0.31, P CBS = 0.26, PNBC = 0.27, PIND = 0.16
H: The proportions are not PABC = 0.31, PCBS = 0.26, PNBC = 0.27, PIND - 0.16.
%3D
Ho: PABC
H: PABC
0.31, PCBS
0.26, PNBC = 0.27, PIND = 0.16
%3D
%3D
+ 0.31, PCBS
* 0.26, PNBC
* 0.27, PIND
* 0.16
Ho: The proportions are not PARC
0.31, PCBS = 0.26, PNBC = 0.27, PIND = 0.16.
= 0.27, PIND = 0.16
Ha: PABC = 0.31, P CBS = 0.26, PNBC
%3D
= 0.31, PCBs * 0.26, PNBC
H: PABC = 0.31, PCBS = 0.26, p NBC = 0.27, PIND - 0.16
Ho: PABC
* 0.27, PIND * 0.16
!!
Find the value of the test statistic. (Round your answer to three decimal places.)
Find the p-value. (Round your answer to four decimal places.)
p-value =
State your conclusion.
Reject H. There has been a significant change in the viewing audience proportions.
Reject Ho. There has not been a significant change in the viewing audience proportions.
Do not reject Hp. There has been a significant change in the viewing audience proportions.
Do not reject Ho:
There has not been a significant change in the viewing audience proportions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F492b0bc9-f5c2-4f30-88ae-8dff02e437ac%2Fb11d1c63-57af-4b1a-bfec-761fab0a5cbe%2Fmz1mis_processed.jpeg&w=3840&q=75)
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