During one shift, the express lane clerk recorded how many times customers violated the "10 items or less" rule for his lane. In particular, he recorded how many items over the limit each violator placed on the conveyor belt. This data is summarized in the histogram below. NOTE: The last class actually represents "7 or more items," not just 7 items. Frequency 12 10- 8 6 0.5 1.5 2.5 3.5 4.5 5.5 6.5 7.5 Q # items over 10 What is the frequency of times the limit was exceeded by at least 3 items? ans =
During one shift, the express lane clerk recorded how many times customers violated the "10 items or less" rule for his lane. In particular, he recorded how many items over the limit each violator placed on the conveyor belt. This data is summarized in the histogram below. NOTE: The last class actually represents "7 or more items," not just 7 items. Frequency 12 10- 8 6 0.5 1.5 2.5 3.5 4.5 5.5 6.5 7.5 Q # items over 10 What is the frequency of times the limit was exceeded by at least 3 items? ans =
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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
Transcribed Image Text:During one shift, the express lane clerk recorded how many times customers violated the "10 items or less" rule for his lane. In particular, he recorded how many items over the limit each violator placed on the conveyor belt. This data is summarized in the histogram below. NOTE: The last class actually represents "7 or more items," not just 7 items.
**Histogram Explanation:**
- The histogram has the x-axis labeled as "# items over 10" and the y-axis as "Frequency."
- The data is divided into intervals, or "bins," each representing the number of items over the 10-item limit.
- The first bin (0.5 to 1.5 items over) has a frequency of 6.
- The second bin (1.5 to 2.5 items over) has a frequency of 8.
- The third bin (2.5 to 3.5 items over) has a frequency of 11.
- The fourth bin (3.5 to 4.5 items over) has the highest frequency at 12.
- The fifth bin (4.5 to 5.5 items over) has a frequency of 10.
- The sixth bin (5.5 to 6.5 items over) has a frequency of 8.
- The last bin (6.5 to 7.5 items over, representing 7 or more) has a frequency of 5.
What is the frequency of times the limit was exceeded by at least 3 items?
**Answer Calculation:**
To find the frequency of times the limit was exceeded by at least 3 items, add the frequencies from the third bin onward:
11 (3.5) + 12 (4.5) + 10 (5.5) + 8 (6.5) + 5 (7.5) = 46
**ans = 46**
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