During a certain time interval, the angular position of a swinging door is described by 0 = 5.06 + 10.5t + 2.02t2, where 0 is in radians and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the door at the following times. (a) t = 0 rad rad/s a = rad/s2 (b) t = 3.04 s rad rad/s a = rad/s?

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**Topic: Analyzing the Motion of a Rotating Door**

**Problem Statement:**

During a certain time interval, the angular position of a swinging door is described by the equation:

\[ \theta = 5.06 + 10.5t + 2.02t^2 \]

where \(\theta\) is in radians and \(t\) is in seconds. Determine the angular position, angular speed, and angular acceleration of the door at the following times:

**(a) \(t = 0\):**

- \(\theta = \_\_\_\_\_\_\_ \, \text{rad}\)
- \(\omega = \_\_\_\_\_\_\_ \, \text{rad/s}\)
- \(\alpha = \_\_\_\_\_\_\_ \, \text{rad/s}^2\)

**(b) \(t = 3.04 \, \text{s}\):**

- \(\theta = \_\_\_\_\_\_\_ \, \text{rad}\)
- \(\omega = \_\_\_\_\_\_\_ \, \text{rad/s}\)
- \(\alpha = \_\_\_\_\_\_\_ \, \text{rad/s}^2\)

**Explanation:**

1. **Angular Position (\(\theta\))**: The equation provides the angular position as a function of time. By substituting the given time values into the equation, students can calculate the angular position at specific times.

2. **Angular Speed (\(\omega\))**: This is the first derivative of the angular position with respect to time. By differentiating the given equation with respect to time, students can determine the angular speed.

3. **Angular Acceleration (\(\alpha\))**: This is the derivative of angular speed with respect to time, or the second derivative of angular position. By differentiating the angular speed equation, students can calculate the angular acceleration.

This exercise helps students understand how to derive key rotational motion parameters from a function describing angular position over time.
Transcribed Image Text:**Topic: Analyzing the Motion of a Rotating Door** **Problem Statement:** During a certain time interval, the angular position of a swinging door is described by the equation: \[ \theta = 5.06 + 10.5t + 2.02t^2 \] where \(\theta\) is in radians and \(t\) is in seconds. Determine the angular position, angular speed, and angular acceleration of the door at the following times: **(a) \(t = 0\):** - \(\theta = \_\_\_\_\_\_\_ \, \text{rad}\) - \(\omega = \_\_\_\_\_\_\_ \, \text{rad/s}\) - \(\alpha = \_\_\_\_\_\_\_ \, \text{rad/s}^2\) **(b) \(t = 3.04 \, \text{s}\):** - \(\theta = \_\_\_\_\_\_\_ \, \text{rad}\) - \(\omega = \_\_\_\_\_\_\_ \, \text{rad/s}\) - \(\alpha = \_\_\_\_\_\_\_ \, \text{rad/s}^2\) **Explanation:** 1. **Angular Position (\(\theta\))**: The equation provides the angular position as a function of time. By substituting the given time values into the equation, students can calculate the angular position at specific times. 2. **Angular Speed (\(\omega\))**: This is the first derivative of the angular position with respect to time. By differentiating the given equation with respect to time, students can determine the angular speed. 3. **Angular Acceleration (\(\alpha\))**: This is the derivative of angular speed with respect to time, or the second derivative of angular position. By differentiating the angular speed equation, students can calculate the angular acceleration. This exercise helps students understand how to derive key rotational motion parameters from a function describing angular position over time.
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