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"Dunouf puR O a) Compute the values of the node voltages Ve and Vp,a. Vin = 6 V b) Compute the values of the node voltages Ve and Vp, a Vin = 1 V 10 10 V V. Vin o R R 7V- Transistor's characteristic equations: Ic = 0 if (Ve-Vs) if 0< (Vp – V- if In 200 (V-Vs-1.5)(Vp – Vg) 200 (Vc-Vs – 1.5)2 (V, – V

"Dunouf puR O a) Compute the values of the node voltages Ve and Vp,a. Vin = 6 V b) Compute the values of the node voltages Ve and Vp, a Vin = 1 V 10 10 V V. Vin o R R 7V- Transistor's characteristic equations: Ic = 0 if (Ve-Vs) if 0< (Vp – V- if In 200 (V-Vs-1.5)(Vp – Vg) 200 (Vc-Vs – 1.5)2 (V, – V

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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An input signal Vin drives an operational amplifier, and the output of the operational amplifier drives a transistor. For reference, the output terminal is the node labeled Vp. The characteristic equations of the transistor are provided below. The op-amp can be considered ideal, and is powered by a 10 V voltage source and ground. a) Compute the values of the node voltages VG and Vp, and the current Ip, when the input voltage is Vin = 6 V b) Compute the values of the node voltages Vc and Vp, and the current Ip, when the input voltage is Vin = 1V 1000 N 1000 V VD 10 V Ip VG Vin Transistor (three terminal circuit element) IG Vs Is 7 V- R R Transistor's characteristic equations: Ic = 0 (Ve - Vs) s 1.5 Ip ={200 (VG - Vs – 1.5)(Vp – Vs) 200 (Ve-Vs-1.5)? if if 0< (Vp – Vs) s (Vc – Vs – 1.5) (Vp - Vs) > (VG - Vs – 1.5) if
Transcribed Image Text:An input signal Vin drives an operational amplifier, and the output of the operational amplifier drives a transistor. For reference, the output terminal is the node labeled Vp. The characteristic equations of the transistor are provided below. The op-amp can be considered ideal, and is powered by a 10 V voltage source and ground. a) Compute the values of the node voltages VG and Vp, and the current Ip, when the input voltage is Vin = 6 V b) Compute the values of the node voltages Vc and Vp, and the current Ip, when the input voltage is Vin = 1V 1000 N 1000 V VD 10 V Ip VG Vin Transistor (three terminal circuit element) IG Vs Is 7 V- R R Transistor's characteristic equations: Ic = 0 (Ve - Vs) s 1.5 Ip ={200 (VG - Vs – 1.5)(Vp – Vs) 200 (Ve-Vs-1.5)? if if 0< (Vp – Vs) s (Vc – Vs – 1.5) (Vp - Vs) > (VG - Vs – 1.5) if
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