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Due to the force of magnitude magnitude 110N applied on the jockey pulley, the top of the slack side of the belt engages the smaller pulley horizontally. It is understood that the tension in the slack side of the belt remains the same at both ends of the inserted jockey pulley. Diameters are respectively , = 700 mm for the driven pulley and da = 310 for the driver with a coefficient of friction of and 0.28 between the belt and each pulley. Pulleys are mounted on parallel axes kept z = 1.25m apart. Angle e = 65° between the radius (tangential to the belt) and the horizontal is not to be confused with contact angles. Analyse the belt drive system and calculate: The contact angles of the open belt drive (without the jockey pulley) are respectively 0g =| | rad on the driver side and 0, =| rad on the machine/driven side. The take-up pulley keeps the top/lack side of the belt horizontal on top of the driver pulley, resulting in a modified contact angle of rad at the driver pulley. As a result of the reaction of of magnitde 110N due to the take-up pulley, the tensile force in the slack side of the beit is F, = | |N and the tension in the tight side of the belt |N. The linear speed of the belt is |m/s and a total power of | kW is transmitted. In a further experiment, the tension in the slack side of the belt is maintained, the frictions parameters, the distance between axes and the respective diameters remain the same. The take up pulley is removed . Analyze the resulting the open belt drive and determine the corresponding tension in the tight side F, = | N under new conditions. The power transmitted by the new in the open belt arrangement is W .One can conciude that using the take up pulley

Due to the force of magnitude magnitude 110N applied on the jockey pulley, the top of the slack side of the belt engages the smaller pulley horizontally. It is understood that the tension in the slack side of the belt remains the same at both ends of the inserted jockey pulley. Diameters are respectively , = 700 mm for the driven pulley and da = 310 for the driver with a coefficient of friction of and 0.28 between the belt and each pulley. Pulleys are mounted on parallel axes kept z = 1.25m apart. Angle e = 65° between the radius (tangential to the belt) and the horizontal is not to be confused with contact angles. Analyse the belt drive system and calculate: The contact angles of the open belt drive (without the jockey pulley) are respectively 0g =| | rad on the driver side and 0, =| rad on the machine/driven side. The take-up pulley keeps the top/lack side of the belt horizontal on top of the driver pulley, resulting in a modified contact angle of rad at the driver pulley. As a result of the reaction of of magnitde 110N due to the take-up pulley, the tensile force in the slack side of the beit is F, = | |N and the tension in the tight side of the belt |N. The linear speed of the belt is |m/s and a total power of | kW is transmitted. In a further experiment, the tension in the slack side of the belt is maintained, the frictions parameters, the distance between axes and the respective diameters remain the same. The take up pulley is removed . Analyze the resulting the open belt drive and determine the corresponding tension in the tight side F, = | N under new conditions. The power transmitted by the new in the open belt arrangement is W .One can conciude that using the take up pulley

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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Due to the force of magnitude magnitude 110N applied on the jockey pulley, the top of the slack side of the belt engages the smaller pulley horizontally. It is understood that the tension in the slack side of the belt remains the same at both ends of the inserted jockey pulley. Diameters are respectively m = 700 mm for the driven pulley and Đa = 310 for the driver with a coefficient of friction of and 0.28 between the belt and each pulley. Pulleys are mounted on parallel axes kept r = 1.25m apart. Angle 0 = 65° between the radius (tangential to the belt) and the horizontal is not to be confused with contact angles. Analyse the belt drive system and calculate: The contact angles of the open belt drive (without the jockey pulley) are respectively Oa rad on the driver side and em = rad on the machine/driven side. The take-up pulley keeps the top/lack side of the belt horizontal on top of the driver pulley, resulting in a modified contact angle of rad at the driver pulley. As a result of the reaction of of magnitde 110N due to the take-up pulley, the tensile force in the slack side of the belt is F2 = N and the tension in the tight side of the belt N. The linear speed of the belt is | m/s and a total power of| kW is transmitted. In a further experiment, the tension in the slack side of the belt is maintained, the frictions parameters, the distance between axes and the respective diameters remain the same. The take up pulley is removed . Analyze the resulting the open belt drive and detemine the corresponding tension in the tight side F. N under new conditions. The power transmitted by the new in the open belt arrangement is W.One can conclude that using the take up pulley
Transcribed Image Text:Due to the force of magnitude magnitude 110N applied on the jockey pulley, the top of the slack side of the belt engages the smaller pulley horizontally. It is understood that the tension in the slack side of the belt remains the same at both ends of the inserted jockey pulley. Diameters are respectively m = 700 mm for the driven pulley and Đa = 310 for the driver with a coefficient of friction of and 0.28 between the belt and each pulley. Pulleys are mounted on parallel axes kept r = 1.25m apart. Angle 0 = 65° between the radius (tangential to the belt) and the horizontal is not to be confused with contact angles. Analyse the belt drive system and calculate: The contact angles of the open belt drive (without the jockey pulley) are respectively Oa rad on the driver side and em = rad on the machine/driven side. The take-up pulley keeps the top/lack side of the belt horizontal on top of the driver pulley, resulting in a modified contact angle of rad at the driver pulley. As a result of the reaction of of magnitde 110N due to the take-up pulley, the tensile force in the slack side of the belt is F2 = N and the tension in the tight side of the belt N. The linear speed of the belt is | m/s and a total power of| kW is transmitted. In a further experiment, the tension in the slack side of the belt is maintained, the frictions parameters, the distance between axes and the respective diameters remain the same. The take up pulley is removed . Analyze the resulting the open belt drive and detemine the corresponding tension in the tight side F. N under new conditions. The power transmitted by the new in the open belt arrangement is W.One can conclude that using the take up pulley
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