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ductive step below: Select the mathematical statements to correctly fill in the beginning of the proof of an We will assume for k 21 that 7 evenly divides 62k-1 and will prove that 7 evenly divides 64k+1) - 1. Since, by the inductive hypothesis, 7 evenly divides 62k -1, then 62 can be expressed as (A?), where m is an integer. 62k+1) –1 = 6? . 6 - 1 = (B?) by the ind. hyp. = ... O (A): 7m (B): 36(7m)-1 O (A): 7m (B): 36 (624) - 1 O (A): 7m+1 (B): 36(7m+1)-1 O (A): 7m+1 (B): 36 (6²*) – 1

ductive step below: Select the mathematical statements to correctly fill in the beginning of the proof of an We will assume for k 21 that 7 evenly divides 62k-1 and will prove that 7 evenly divides 64k+1) - 1. Since, by the inductive hypothesis, 7 evenly divides 62k -1, then 62 can be expressed as (A?), where m is an integer. 62k+1) –1 = 6? . 6 - 1 = (B?) by the ind. hyp. = ... O (A): 7m (B): 36(7m)-1 O (A): 7m (B): 36 (624) - 1 O (A): 7m+1 (B): 36(7m+1)-1 O (A): 7m+1 (B): 36 (6²*) – 1

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Select the mathematical statements to correctly fill in the beginning of the proof of an inductive step below: 1. Since, by We will assume for k 21 that 7 evenly divides 62k the inductive hypothesis, 7 evenly divides 62k - 1 and will prove that 7 evenly divides 62(k+1) 1, then 6 can be expressed as (A?), where m is an integer. 62(k+1) -1 = 6.6 - 1 %3D = (B?) by the ind. hyp. %3D = ... O (A): 7m (B): 36(7m)-1 O (A): 7m (B): 36 (62*) – 1 O (A): 7m+1 (B): 36(7m+1)-1 (A): 7m+1 (B): 36 (6*) – 1
Transcribed Image Text:Select the mathematical statements to correctly fill in the beginning of the proof of an inductive step below: 1. Since, by We will assume for k 21 that 7 evenly divides 62k the inductive hypothesis, 7 evenly divides 62k - 1 and will prove that 7 evenly divides 62(k+1) 1, then 6 can be expressed as (A?), where m is an integer. 62(k+1) -1 = 6.6 - 1 %3D = (B?) by the ind. hyp. %3D = ... O (A): 7m (B): 36(7m)-1 O (A): 7m (B): 36 (62*) – 1 O (A): 7m+1 (B): 36(7m+1)-1 (A): 7m+1 (B): 36 (6*) – 1
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