ds = a Σ dt. N = Σ ector field is F1 = 10xi – 7yj, then we have the flux being / (F1 · N)ds. F,(r(t)) (10a(cost))i-(7a(sint))j Σ As such, / . (F1 · N) ds = (10(cos^2t))-(7a(sin^2t)) E our vector field is F2 = 3xi + 9(x – y)j, then we have the flux being (F2 · N)ds.

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