A soil profile is shown in Figure P3.3 along with the standardpenetration numbers in the clay layer. Use Eqs. (3.8b)and (3.9) to determine the variation of cu and OCR withdepth. What is the average value of cu and OCR? Dry sandy = 16.5 kN/m1.5 mGroundwaterEquations belowtableSand1.5 m(3.8b)Ysat = 19 kN/m31.5 m•8Cu= 0.24NO72PaClayYat = 16.8 kN/m31.5 m* A •81.5 m•9(3.9)1.5 m10Sand/N \0.689N60OCR = 0.193FIGURE P3.3

Over consolidation ratio: The ratio of Maximum applied effective stress at a point before and the…

Dry sand y = 16.5 kN/m 1.5 m Groundwater Equations below table Sand 1.5 m (3.8b) Ysat = 19 kN/m3 1.5 m •8 Cu = 0.24NO72 Pa Clay Yat = 16.8 kN/m3 1.5 m * A •8 1.5 m •9 (3.9) 1.5 m 10 Sand /N \0.689 N60 OCR = 0.193 FIGURE P3.3

Dry sand y = 16.5 kN/m 1.5 m Groundwater Equations below table Sand 1.5 m (3.8b) Ysat = 19 kN/m3 1.5 m •8 Cu = 0.24NO72 Pa Clay Yat = 16.8 kN/m3 1.5 m * A •8 1.5 m •9 (3.9) 1.5 m 10 Sand /N \0.689 N60 OCR = 0.193 FIGURE P3.3

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Sediment transport

Sediment transport or Soil transport is the movement of solid particles, usually due to the combination of gravitational forces acting on the sediment, and the movement of the liquid at which the sediment enters. Soil erosion occurs in natural systems where the particles are sandstones (sand, rocks), mud, or clay; the liquid is air, water, or ice; and the gravitational force that works to move particles to the landing surface. Sediment transportation or soil migration due to the movement of liquids occurs in rivers, lakes, lakes, oceans, and other bodies of water as a result of currents and waves. Transportation is also caused by glaciers as they flow, and to places on earth under the influence of wind. Soil erosion due to gravity alone is possible in most sloping areas, including hills, scarves, cliffs, and the continental shelf — the continental boundary of the slope.

Question

A soil profile is shown in Figure P3.3 along with the standard
penetration numbers in the clay layer. Use Eqs. (3.8b)
and (3.9) to determine the variation of cu and OCR with
depth. What is the average value of cu and OCR?

Dry sand
y = 16.5 kN/m
1.5 m
Groundwater
Equations below
table
Sand
1.5 m
(3.8b)
Ysat = 19 kN/m3
1.5 m
•8
Cu
= 0.24NO72
Pa
Clay
Yat = 16.8 kN/m3
1.5 m
* A •8
1.5 m
•9
(3.9)
1.5 m
10
Sand
/N \0.689
N60
OCR = 0.193
FIGURE P3.3

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