drs 500 10⁰ v GIVEN: 1032 M ST 2012 40. 1, 500 27= 73.422 -37,409 IT = 6.81 137.409 A 302 # 60-2 FIND: F. APPARENT POWER: S = X ₁ Iq = G. PHASE DIFFERENCE & p.t. 12 DRAW THE FRVIVALENT SERIES Yr 2 ZT 2 1,13 802 70-2 fr² zr CONNECTION 14 9052 1003
drs 500 10⁰ v GIVEN: 1032 M ST 2012 40. 1, 500 27= 73.422 -37,409 IT = 6.81 137.409 A 302 # 60-2 FIND: F. APPARENT POWER: S = X ₁ Iq = G. PHASE DIFFERENCE & p.t. 12 DRAW THE FRVIVALENT SERIES Yr 2 ZT 2 1,13 802 70-2 fr² zr CONNECTION 14 9052 1003
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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![Vrs 5000 v
GIVEN:
102
M
IT
HE
202
11.7 DRAW
1.) 1
40.
27= 73.422 37.409
I₁ = 6.81 137.1409 A
[₁
1
Req
500
FIND:
F. APPARENT POWER: S = X₁ [₁ =
G.) PHASE DIFFERENCE & p.t.
zeq
J.) Rea and Yea
302
A
60-2
THE EQUIVALENT SERIES
1
xea
Yr 2
ZT
1,13
802
z fr ² zr
70-2
CONNECTION
14
9052
100](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F63792d50-862a-477a-90e7-26b0e3ee6e5e%2Ff5e4bea8-d3a4-4b8d-af0f-4f7b14e12bd4%2Fporhr0p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Vrs 5000 v
GIVEN:
102
M
IT
HE
202
11.7 DRAW
1.) 1
40.
27= 73.422 37.409
I₁ = 6.81 137.1409 A
[₁
1
Req
500
FIND:
F. APPARENT POWER: S = X₁ [₁ =
G.) PHASE DIFFERENCE & p.t.
zeq
J.) Rea and Yea
302
A
60-2
THE EQUIVALENT SERIES
1
xea
Yr 2
ZT
1,13
802
z fr ² zr
70-2
CONNECTION
14
9052
100
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