drs 500 10⁰ v GIVEN: 1032 M ST 2012 40. 1, 500 27= 73.422 -37,409 IT = 6.81 137.409 A 302 # 60-2 FIND: F. APPARENT POWER: S = X ₁ Iq = G. PHASE DIFFERENCE & p.t. 12 DRAW THE FRVIVALENT SERIES Yr 2 ZT 2 1,13 802 70-2 fr² zr CONNECTION 14 9052 1003

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Vrs 5000 v
GIVEN:
102
M
IT
HE
202
11.7 DRAW
1.) 1
40.
27= 73.422 37.409
I₁ = 6.81 137.1409 A
[₁
1
Req
500
FIND:
F. APPARENT POWER: S = X₁ [₁ =
G.) PHASE DIFFERENCE & p.t.
zeq
J.) Rea and Yea
302
A
60-2
THE EQUIVALENT SERIES
1
xea
Yr 2
ZT
1,13
802
z fr ² zr
70-2
CONNECTION
14
9052
100
Transcribed Image Text:Vrs 5000 v GIVEN: 102 M IT HE 202 11.7 DRAW 1.) 1 40. 27= 73.422 37.409 I₁ = 6.81 137.1409 A [₁ 1 Req 500 FIND: F. APPARENT POWER: S = X₁ [₁ = G.) PHASE DIFFERENCE & p.t. zeq J.) Rea and Yea 302 A 60-2 THE EQUIVALENT SERIES 1 xea Yr 2 ZT 1,13 802 z fr ² zr 70-2 CONNECTION 14 9052 100
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