Drive a mathematic formula to calculate the capacitance of half hollow cylinder with inner radius a and outer radius b considering the two plates of the capacitance are1- side surfaces (inner and outer) of the half hollow cylinder.2- top and bottom surfaces of the half hollow cylinder. where the half hollow cylinder is shown

Drive a mathematic formula to calculate the capacitance of half hollow cylinder with inner radius a and outer radius b considering the two plates of the capacitance are1- side surfaces (inner and outer) of the half hollow cylinder.2- top and bottom surfaces of the half hollow cylinder. where the half hollow cylinder is shown

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

Explain the modifciation to be made to the schering bridge for the following situations: i) Hihg dissipation factor test objects II) High capacitance test objects Explain in easy language so i can understand
A cylindrical long solenoid of length 2000 mm has 20 mm diameter. If number of turns wounded on solenoid is 2000 turns what is value of inductance.
A magnetic core with an air gap is shown below. For a relative permeability is 9500, and the space free permeability is 4Ttx107 H/m. Find the reluctance of the left leg and the top side of the core. Ignore the gap in your calculations. 10 cm 0.1 cm gap 20 cm 5 cm 5 cm 40 cm 5 cm core depth = 10 cm Select one: a. Rjeft = 3.770 KA.t./Wb , Rtop = 4.607 KA.t/Wb b. None c. Rieft = 377.0 A.t./Wb , Rtop = 460.7 A.t/Wb d. Rjeft = 325.1 A.t./Wb , Rtop = 402.3 A.t/Wb ----------
A solenoid of 100 turns has a length of 75 cm and the radius of 20 cm. A steel rod of circular cross-section is fitted in the solenoid coaxially. Relative permeability of steel is 3000 and a dc current of 10 A is passed through solenoid. Conclude the inductance of the system, energy stored and the mean flux density inside the solenoid.
Figure shows a circuit and a conducting rod. A conducting rod moves with a constant velocity vperpendicular to a circuit with a current I=2.82sin(??)
Find / Derive the equation for the capacitance of a spherical capacitor, consisting a spherical conducting shell of radius "b" and charge - Q concentric with a smaller conducting sphere of radius "a" and charge Q. Draw the figure.
Question 6 electric ....inductors, or inductors without core material, are used for up to 5 millihenries of inductance. They are wrapped on a ceramic or phenolic core. Full explain this question and text typing work only thanks
FIGURE 5-15 A closely wound toroidal coil (Example 5-8).
Consider the magnetic circuit of with the dimensions of Problem 1.1. Assuming infinite core permeability, calculate (a) the number of turns required to achieve an inductance of 12 mH and (b) the inductor current which will result in a core flux density of 1.0 T. N turns Core: mean length 4. area A permeability Air gap R
2) Vo voltage is applied to the metal parallel plate capacitor system given in the figure. The region between the plates is filled with dielectric material of &-2.4. Bottom plate grounded and d-2mm in the z-axis of the top plate when placed at z=0 are within distance. For tension in the interplate region boundary conditions: If V(z)-0 volts for z-0 and V(z)-Vo volts for z-d; a) Potential expression in the interplate region V=? b) Electric field strength E-? c) Electric flux density D-? d) Surface charge densities of the plates p.=?
Q2. A toroidal core that is made of iron and having relative permeability of µ, = 5000. The mean path length of the core, le is 37.6 cm while the cross-sectional area of the core is 0.1256 cm². The fringing effect and leakage flux are to be negligible. The number of turns of the coil, N¡ is 400. If there is an airgap of 5 mm and magnetic flux density at air gap is 0.25 T, (i) Draw equivalent magnetic circuit analogy of the core. (ii) Calculate the current required to energize the core. (iii) Determine the magnetizing strength, Hg in the air gap. mark (iv) If flux density in the air gap is reduced to half, find the new current flowing in the coil to energize the core. (v) If there is no airgap and the current value is similar as in (ii), what is the flux density in the core ? (Note: lo = 4n x10-7 H/m, Bmax = 1.5 T).
PLEASE CORRECT AND CLEAR SOLUTION PLEASE.VERY IMPORTANT FOR ME .VERY IMPORTANT HOMEWORK Please in typing format please ASAP for like