Divide IP addresses for network ID 172.168.89.0 into two subnets, and divide the network ID 172.16.0.0 (class B IP address) into four subnets. Describe each step and show the result at each step.
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- • IPV6 addresses use 128 bits to represent an address which includes bits to be used for subnetting. The second half of the address (least significant 64 bits) is always used for hosts only. Therefore, there is no compromise if we subnet the network. Use the Figure below to Create five subnets using route prefix 2001:db:acad::/48 (1 Marks) Routing Prefix Subnet ID Interface ID 48 Bits 16 Bits 64 BitsConsider the subnet address 210.84.40.0, divided into 3 subnets. If we want to maximize the number of hosts per subnet, what subnet mask should we use? What would the numbers of the first 2 and last 2 subnets be, along with their address range and their broadcast? Explain your answers.Please help with the following: Consider the network address 199.200.30.0. We want at least two subnets and between 60 and 70 hosts per subnet. What subnet mask should we use? What would the numbers of the first 2 and last 2 subnets be, along with their address range and their broadcast? Explain your answer.
- Internet protocol version 6 (IPV6) has been introduced to replace the previous version (IPV4), Which of the following best describes a benefit of IPV6 over IPV4? A IPV6 addresses are shorter than IPV4 addresses, which allows for faster routing of packets. B IPV6 allows for a greater number of addresses than IPV4, which allows more devices to be connected to the Internet. IPV6 eliminates the use of hierarchy in addressing, making addresses easier to use. D IPV6 allows users to bypass older security protocols so that data can be sent peer-to-peer without the use of routers.4. The original HTTP protocol used TCP/IP as the underlying protocol. For each page, graphic, or applet, a separate TCP connection was constructed, used, and terminated. This caused several problems: one referred to as the elephant and mice problem and two aspects of connection overhead. Describe both problems. Why were separate connections used? Would UDP rather than TCP be a good alternative? What solution would you propose to these problems to improve HTTP performance?Given the network address 148.211.93.128/25, develop a scheme for 3 subnets with at most 10 hosts each. Show the subnet mask and CIDR notation for the subnet scheme. Show the 1st, 2nd, and 3rd subnet addresses and list the range of available IP addresses for each subnet.
- Network Address 172.85.26.0/23 Chippendale LAN 12 Hosts Chippendale Ultimo LAN Glebe LAN 45 Hosts 85 Hosts Ultimo City Glebe City/Glebe LAN 210 Hosts Given the following information and diagram and the IP address 172.85.26.0/23, use VLSM addressing to assign IP addresses for different subnets. Complete the Table with the Network Address and Host Address for different LANS. All host addresses will be the 8th host address in each subnet. Complete the Table with IP address using 'xxx.xxx.XXx.Xxx' without prefix. For example: 192.168.10.15 for IP address rather than 192.168.10.15/24. Host Network Network Address Host Address Requirement 45 Ultimo LAN 12 Chippendale LAN 210 City/Glebe LAN 85 Glebe LANAn ISP is granted a block of addresses starting with 130.100.0.0/16. The ISP needs to distribute these addresses to 4 large companies. Each company requires 1024 IP addresses. Write the address ranges for these companies into the following table with /n notation. Company First address Last address 1 2 3 4If the IP address is 192.168.1.5 , the mask is 255.255.255.240,(1) convert the P address and mask in binary format, (2) give the class of the network, the number of bits for subnet, and the number of bits for hosts, (3) the (network id)/(\# of mask bit) in decimal format, (4) subnet broadcast address in decimal format, and (5) the range of valid hosts addresses in decimal format.
- Given the IP address 194.168.10.23 and the subnet mask 255.255.255.240. Find the following: (a) the number of subnets TOTTIMET0/ b) the number of usable hosts IP address in each subnetLet IP address 200.210.56.76/28 determine the subnet mask, subnet id, broadcast address, and total number of subnets and hosts in subnets. And use a nice illustration to demonstrate Remote monitoring.Design a suitable network for an organization with 5 branches, ensuring the most efficient usage of the IP addresses 195.143.208.133/25, and list all its subnet IDs.