Draw the structure of the product that is formed when the compound shown below is treated with the following reagents: 1) ВНз, ТHF: 2) НаО, НО. Interactive 3D display mode CH3 H,C
Draw the structure of the product that is formed when the compound shown below is treated with the following reagents: 1) ВНз, ТHF: 2) НаО, НО. Interactive 3D display mode CH3 H,C
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:**Title:** Hydroboration-Oxidation Reaction of an Alkene
**Content:**
**Objective:**
Determine the structure of the product formed when the given alkene is treated with the specified reagents.
**Reagents:**
1. \( \text{BH}_3, \text{THF} \)
2. \( \text{H}_2\text{O}_2, \text{HO}^- \)
**Initial Structure:**
The initial molecule is an alkene with the structure:
- A three-carbon chain.
- A double bond between the second (middle) and third carbon atom.
- A methyl group (\( \text{CH}_3 \)) attached to the first carbon.
**Explanation:**
The reaction involves a two-step process:
1. **Hydroboration:**
- Borane (\( \text{BH}_3 \)) adds across the double bond.
- The addition is syn and occurs via an anti-Markovnikov path, meaning the boron attaches to the less substituted carbon.
2. **Oxidation:**
- The organoborane intermediate undergoes oxidation with peroxide (\( \text{H}_2\text{O}_2 \)) and a base (\( \text{HO}^- \)).
- This step replaces the boron with a hydroxyl group (\( \text{OH} \)), resulting in the formation of an alcohol.
**Expected Product Structure:**
Draw the resulting alcohol structure post-reaction, ensuring the hydroxyl group is on the less substituted end of the original double bond.
**Note:**
Explore the reaction in the interactive 3D display mode for a detailed visualization of the structural changes.
End of content.
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