Draw the structure of the major organic product(s) for the following reaction between an acetylenic anion and an alkyl halide. (The reaction stoichiometry is 1:1.) + Na :C=C-CH3 + > -Br Draw the major organic product or products for the reaction. Rings More Select Draw с H Erase Q 2 Q
Draw the structure of the major organic product(s) for the following reaction between an acetylenic anion and an alkyl halide. (The reaction stoichiometry is 1:1.) + Na :C=C-CH3 + > -Br Draw the major organic product or products for the reaction. Rings More Select Draw с H Erase Q 2 Q
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Title: Understanding the Reaction Between an Acetylenic Anion and an Alkyl Halide**
**Objective:**
Learn to draw the structure of the major organic product(s) for the reaction between an acetylenic anion and an alkyl halide. The reaction stoichiometry is 1:1.
**Chemical Equation:**
- Reactants:
- Sodium acetylide ion \((\text{Na}^+:\text{C}\equiv\text{C-CH}_3)\)
- Alkyl halide (1-bromo-2-methylpropane)
**Reaction Mechanism:**
The acetylenic anion acts as a nucleophile, replacing the bromine atom in the alkyl halide via an SN2 reaction mechanism. This forms a new carbon-carbon bond.
**Product:**
A compound with an extended carbon chain containing the alkyne group is formed:
- The drawn structure depicts an alkyne chain connected to a branching alkyl group. The alkyl group is attached at the secondary carbon, showcasing the characteristic zigzag pattern of a carbon-carbon triple bond.
**Summary:**
This exercise emphasizes the formation of a carbon-carbon bond through nucleophilic substitution. It provides valuable insight into the manipulation of organic compounds using acetylenic anions in synthetic chemistry.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9c736d07-d75d-4ba3-b07b-66393d09ab70%2Fc30cd005-266f-4629-9bdf-902347380823%2Fn0bh7kl_processed.png&w=3840&q=75)
Transcribed Image Text:**Title: Understanding the Reaction Between an Acetylenic Anion and an Alkyl Halide**
**Objective:**
Learn to draw the structure of the major organic product(s) for the reaction between an acetylenic anion and an alkyl halide. The reaction stoichiometry is 1:1.
**Chemical Equation:**
- Reactants:
- Sodium acetylide ion \((\text{Na}^+:\text{C}\equiv\text{C-CH}_3)\)
- Alkyl halide (1-bromo-2-methylpropane)
**Reaction Mechanism:**
The acetylenic anion acts as a nucleophile, replacing the bromine atom in the alkyl halide via an SN2 reaction mechanism. This forms a new carbon-carbon bond.
**Product:**
A compound with an extended carbon chain containing the alkyne group is formed:
- The drawn structure depicts an alkyne chain connected to a branching alkyl group. The alkyl group is attached at the secondary carbon, showcasing the characteristic zigzag pattern of a carbon-carbon triple bond.
**Summary:**
This exercise emphasizes the formation of a carbon-carbon bond through nucleophilic substitution. It provides valuable insight into the manipulation of organic compounds using acetylenic anions in synthetic chemistry.
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