Draw the structural formula for the intermediate species that forms when the following compound is treated with K,Cr207. CH3 K2Cr207 CH3CHCH2OH H2804 • You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. P opy aste C
Draw the structural formula for the intermediate species that forms when the following compound is treated with K,Cr207. CH3 K2Cr207 CH3CHCH2OH H2804 • You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. P opy aste C
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Draw the structural formula for the intermediate species that forms when the following compound is treated with \( \text{K}_2\text{Cr}_2\text{O}_7 \).
\[
\begin{array}{c}
\quad \quad \quad \quad \quad \quad \quad \quad \quad \text{CH}_3 \\
\quad \quad \quad \quad \quad \quad \quad \quad \quad | \\
\text{CH}_3\text{CHCH}_2\text{OH} \quad \xrightarrow{\text{K}_2\text{Cr}_2\text{O}_7, \, \text{H}_2\text{SO}_4} \quad ?
\end{array}
\]
- You do not have to consider stereochemistry.
- You do not have to explicitly draw H atoms.
Below the instructions, there is a blank area with drawing tools for illustrating the molecular structure.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7ce8a70f-b581-4060-af6c-1e60c4e3d54e%2F6ad0d6cf-b3cb-4728-83c1-b285e6453b04%2F49am1d_processed.png&w=3840&q=75)
Transcribed Image Text:Draw the structural formula for the intermediate species that forms when the following compound is treated with \( \text{K}_2\text{Cr}_2\text{O}_7 \).
\[
\begin{array}{c}
\quad \quad \quad \quad \quad \quad \quad \quad \quad \text{CH}_3 \\
\quad \quad \quad \quad \quad \quad \quad \quad \quad | \\
\text{CH}_3\text{CHCH}_2\text{OH} \quad \xrightarrow{\text{K}_2\text{Cr}_2\text{O}_7, \, \text{H}_2\text{SO}_4} \quad ?
\end{array}
\]
- You do not have to consider stereochemistry.
- You do not have to explicitly draw H atoms.
Below the instructions, there is a blank area with drawing tools for illustrating the molecular structure.
![**Question:**
What is the IUPAC name of the following compound?
**Diagram Explanation:**
The diagram shows a structural formula of a chemical compound with the following arrangement:
- The central carbon (C) is bonded to a thiol group (SH).
- It has three additional bonds to methyl groups (CH₃).
**Answer Box:**
[ ]
**Explanation:**
This compound is a thiol with a central carbon, indicating that it has three branches of CH₃ groups attached to the central carbon. The presence of SH (thiol) indicates this compound is named as a thiol.
**Educational Note:**
In naming this compound with the IUPAC system, the main focus is on identifying the longest carbon chain and functional group presence. Here, the carbon with the SH group is the parent chain, and the methyl groups are branches.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7ce8a70f-b581-4060-af6c-1e60c4e3d54e%2F6ad0d6cf-b3cb-4728-83c1-b285e6453b04%2Fldyukws_processed.png&w=3840&q=75)
Transcribed Image Text:**Question:**
What is the IUPAC name of the following compound?
**Diagram Explanation:**
The diagram shows a structural formula of a chemical compound with the following arrangement:
- The central carbon (C) is bonded to a thiol group (SH).
- It has three additional bonds to methyl groups (CH₃).
**Answer Box:**
[ ]
**Explanation:**
This compound is a thiol with a central carbon, indicating that it has three branches of CH₃ groups attached to the central carbon. The presence of SH (thiol) indicates this compound is named as a thiol.
**Educational Note:**
In naming this compound with the IUPAC system, the main focus is on identifying the longest carbon chain and functional group presence. Here, the carbon with the SH group is the parent chain, and the methyl groups are branches.
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