Draw the shear and moment diagrams for the loaded beam. After you have the diagrams, answer the questions as a check on your work.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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## Beam Analysis

### Problem Statement:
Draw the shear and moment diagrams for the loaded beam. After you have the diagrams, answer the questions as a check on your work.

### Beam Description:
The beam is subject to the following loads:
- Uniformly distributed load of 4 kN/m over the first 7 meters from point A.
- A point load of 26 kN located 11 meters from point A.
- Triangular distributed load with a maximum intensity of 6 kN/m over the remaining 15 meters to point B.

### Beam Dimensions:
- From A to B: Total length of 26 meters.
- Distances: 
  - 7 m from A to start of triangular load.
  - Triangular load spans 15 m after the 4 m gap past the point load.

### Questions and Calculated Values:
- **When x = 3.2 m:**
  - Shear force \( V = -12.8 \) kN
  - Bending moment \( M = -20.48 \) kN·m
  
- **When x = 8.1 m:**
  - Shear force \( V = 43.783 \) kN
  - Bending moment \( M = -49.8387 \) kN·m
  
- **When x = 12.3 m:**
  - Shear force \( V = 17.783 \) kN
  - Bending moment \( M = 100.249 \) kN·m
  
- **When x = 20.1 m:**
  - Shear force \( V = 12.581 \) kN
  - Bending moment \( M = 230.1139 \) kN·m

### Maximum Values:
- Maximum (absolute value) shear force in the beam:
  \(|V_{\text{max}}| = 43.783\) kN

- Maximum (absolute value) bending moment in the beam:
  \(|M_{\text{max}}| = 260.0536\) kN·m

### Diagrams:
The shear and moment diagrams are not shown directly here but should be derived from these data points, showing the variations of shear force and bending moment along the length of the beam.

### Analysis:
- Using the given forces and load distribution, calculate reaction forces at supports.
- Plot the shear force
Transcribed Image Text:## Beam Analysis ### Problem Statement: Draw the shear and moment diagrams for the loaded beam. After you have the diagrams, answer the questions as a check on your work. ### Beam Description: The beam is subject to the following loads: - Uniformly distributed load of 4 kN/m over the first 7 meters from point A. - A point load of 26 kN located 11 meters from point A. - Triangular distributed load with a maximum intensity of 6 kN/m over the remaining 15 meters to point B. ### Beam Dimensions: - From A to B: Total length of 26 meters. - Distances: - 7 m from A to start of triangular load. - Triangular load spans 15 m after the 4 m gap past the point load. ### Questions and Calculated Values: - **When x = 3.2 m:** - Shear force \( V = -12.8 \) kN - Bending moment \( M = -20.48 \) kN·m - **When x = 8.1 m:** - Shear force \( V = 43.783 \) kN - Bending moment \( M = -49.8387 \) kN·m - **When x = 12.3 m:** - Shear force \( V = 17.783 \) kN - Bending moment \( M = 100.249 \) kN·m - **When x = 20.1 m:** - Shear force \( V = 12.581 \) kN - Bending moment \( M = 230.1139 \) kN·m ### Maximum Values: - Maximum (absolute value) shear force in the beam: \(|V_{\text{max}}| = 43.783\) kN - Maximum (absolute value) bending moment in the beam: \(|M_{\text{max}}| = 260.0536\) kN·m ### Diagrams: The shear and moment diagrams are not shown directly here but should be derived from these data points, showing the variations of shear force and bending moment along the length of the beam. ### Analysis: - Using the given forces and load distribution, calculate reaction forces at supports. - Plot the shear force
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