Draw the shear and moment diagrams for the beam shown below. 10k 8k 8k.ft 10 k.ft 6 k.ft E-8.75 k A,=9.25 k 4 ft 8 ft 4 ft
Draw the shear and moment diagrams for the beam shown below. 10k 8k 8k.ft 10 k.ft 6 k.ft E-8.75 k A,=9.25 k 4 ft 8 ft 4 ft
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:The image is a diagram of a beam showing various forces acting on it, intended for creating shear and moment diagrams. Here's a detailed description:
**Beam Layout:**
- The beam is horizontal, supported at points labeled A and E.
**Distances:**
- The total length of the beam is 16 feet, divided into three segments:
- 4 feet from point A to point B
- 8 feet from point B to point C
- 4 feet from point C to point E
**Forces and Moments:**
- At point A:
- Vertical force \( A_y = 9.25 \, \text{kips (k)} \) pointing upwards.
- Between points B and C:
- A counterclockwise moment of \( 10 \, \text{kips (k)}\cdot\text{ft} \).
- At point D:
- A clockwise moment of \( 6 \, \text{kips (k)}\cdot\text{ft} \).
- At point E:
- Vertical force \( E_y = 8.75 \, \text{kips (k)} \) pointing upwards.
- Downward loads:
- \( 10 \, \text{kips (k)} \) at point B.
- \( 8 \, \text{kips (k)} \) at point C.
**Instructions:**
- The task is to draw the shear force and bending moment diagrams for this beam.
This setup serves as a practical example for students learning to analyze beams in static equilibrium, calculate reactions at supports, and construct shear and moment diagrams.
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