Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Title: Alkynes and Nucleophilic Substitution Reactions**
**Problem Statement:**
Draw the product of this reaction. Ignore inorganic byproducts.
**Reaction Overview:**
- **Starting Material:** A compound featuring a branched alkene with a terminal alkyne group.
- **Reagents:**
1. Sodium amide (NaNH₂)
2. Ethyl bromide (CH₃CH₂Br)
An arrow pointing downward leads to a box labeled "Drawing," indicating where the reaction product should be visualized.
**Explanation:**
In this reaction, the alkyne undergoes a nucleophilic substitution. Sodium amide, acting as a strong base, deprotonates the terminal alkyne hydrogen, forming a nucleophilic acetylide ion. This ion then attacks the ethyl bromide in an SN2 reaction, displacing the bromide ion and forming a new carbon-carbon bond. The final organic product will be an extended alkyne chain with an additional ethyl group linked to its former terminal end.
**Conclusion:**
To complete this exercise, sketch the new molecular structure that results from these transformations, demonstrating understanding of alkyne chemistry and nucleophilic substitution mechanisms.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8f950e16-ff9d-4c3e-b6ed-db2ea86994c5%2F9ba69e35-0187-46ab-81e3-0bf3df5667a1%2Fzian8yl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Alkynes and Nucleophilic Substitution Reactions**
**Problem Statement:**
Draw the product of this reaction. Ignore inorganic byproducts.
**Reaction Overview:**
- **Starting Material:** A compound featuring a branched alkene with a terminal alkyne group.
- **Reagents:**
1. Sodium amide (NaNH₂)
2. Ethyl bromide (CH₃CH₂Br)
An arrow pointing downward leads to a box labeled "Drawing," indicating where the reaction product should be visualized.
**Explanation:**
In this reaction, the alkyne undergoes a nucleophilic substitution. Sodium amide, acting as a strong base, deprotonates the terminal alkyne hydrogen, forming a nucleophilic acetylide ion. This ion then attacks the ethyl bromide in an SN2 reaction, displacing the bromide ion and forming a new carbon-carbon bond. The final organic product will be an extended alkyne chain with an additional ethyl group linked to its former terminal end.
**Conclusion:**
To complete this exercise, sketch the new molecular structure that results from these transformations, demonstrating understanding of alkyne chemistry and nucleophilic substitution mechanisms.
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