Draw the product of this reaction. Ignore inorganic byproducts. 1. NaNH2 2. CH3CH2Br

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Title: Alkynes and Nucleophilic Substitution Reactions**

**Problem Statement:**
Draw the product of this reaction. Ignore inorganic byproducts.

**Reaction Overview:**

- **Starting Material:** A compound featuring a branched alkene with a terminal alkyne group.
  
- **Reagents:**
  1. Sodium amide (NaNH₂)  
  2. Ethyl bromide (CH₃CH₂Br)

An arrow pointing downward leads to a box labeled "Drawing," indicating where the reaction product should be visualized.

**Explanation:**

In this reaction, the alkyne undergoes a nucleophilic substitution. Sodium amide, acting as a strong base, deprotonates the terminal alkyne hydrogen, forming a nucleophilic acetylide ion. This ion then attacks the ethyl bromide in an SN2 reaction, displacing the bromide ion and forming a new carbon-carbon bond. The final organic product will be an extended alkyne chain with an additional ethyl group linked to its former terminal end.

**Conclusion:**

To complete this exercise, sketch the new molecular structure that results from these transformations, demonstrating understanding of alkyne chemistry and nucleophilic substitution mechanisms.
Transcribed Image Text:**Title: Alkynes and Nucleophilic Substitution Reactions** **Problem Statement:** Draw the product of this reaction. Ignore inorganic byproducts. **Reaction Overview:** - **Starting Material:** A compound featuring a branched alkene with a terminal alkyne group. - **Reagents:** 1. Sodium amide (NaNH₂) 2. Ethyl bromide (CH₃CH₂Br) An arrow pointing downward leads to a box labeled "Drawing," indicating where the reaction product should be visualized. **Explanation:** In this reaction, the alkyne undergoes a nucleophilic substitution. Sodium amide, acting as a strong base, deprotonates the terminal alkyne hydrogen, forming a nucleophilic acetylide ion. This ion then attacks the ethyl bromide in an SN2 reaction, displacing the bromide ion and forming a new carbon-carbon bond. The final organic product will be an extended alkyne chain with an additional ethyl group linked to its former terminal end. **Conclusion:** To complete this exercise, sketch the new molecular structure that results from these transformations, demonstrating understanding of alkyne chemistry and nucleophilic substitution mechanisms.
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